diff --git a/problems/0017.电话号码的字母组合.md b/problems/0017.电话号码的字母组合.md index 6f51a181..76d5655d 100644 --- a/problems/0017.电话号码的字母组合.md +++ b/problems/0017.电话号码的字母组合.md @@ -240,7 +240,45 @@ public: Java: +```Java +class Solution { + //设置全局列表存储最后的结果 + List list = new ArrayList<>(); + + public List letterCombinations(String digits) { + if (digits == null || digits.length() == 0) { + return list; + } + //初始对应所有的数字,为了直接对应2-9,新增了两个无效的字符串"" + String[] numString = {"", "", "abc", "def", "ghi", "jkl", "mno", "pqrs", "tuv", "wxyz"}; + //迭代处理 + backTracking(digits, numString, 0); + return list; + + } + + //每次迭代获取一个字符串,所以会设计大量的字符串拼接,所以这里选择更为高效的 StringBuild + StringBuilder temp = new StringBuilder(); + + //比如digits如果为"23",num 为0,则str表示2对应的 abc + public void backTracking(String digits, String[] numString, int num) { + //遍历全部一次记录一次得到的字符串 + if (num == digits.length()) { + list.add(temp.toString()); + return; + } + //str 表示当前num对应的字符串 + String str = numString[digits.charAt(num) - '0']; + for (int i = 0; i < str.length(); i++) { + temp.append(str.charAt(i)); + backTracking(digits, numString, num + 1); + //剔除末尾的继续尝试 + temp.deleteCharAt(temp.length() - 1); + } + } +} +``` Python: