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Update 0344.反转字符串.md
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@ -183,8 +183,8 @@ class Solution:
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"""
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"""
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left, right = 0, len(s) - 1
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left, right = 0, len(s) - 1
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# 该方法已经不需要判断奇偶数,经测试后时间空间复杂度比用 for i in range(right//2)更低
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# 该方法已经不需要判断奇偶数,经测试后时间空间复杂度比用 for i in range(len(s)//2)更低
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# 推荐该写法,更加通俗易懂
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# 因为while每次循环需要进行条件判断,而range函数不需要,直接生成数字,因此时间复杂度更低。推荐使用range
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while left < right:
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while left < right:
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s[left], s[right] = s[right], s[left]
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s[left], s[right] = s[right], s[left]
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left += 1
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left += 1
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