mirror of
https://github.com/youngyangyang04/leetcode-master.git
synced 2025-07-10 04:06:51 +08:00
Update 0106.从中序与后序遍历序列构造二叉树.md
添加 0106.从中序与后序遍历序列构造二叉树 Java版本
This commit is contained in:
@ -582,7 +582,41 @@ tree2 的前序遍历是[1 2 3], 后序遍历是[3 2 1]。
|
||||
|
||||
|
||||
Java:
|
||||
```java
|
||||
class Solution {
|
||||
public TreeNode buildTree(int[] inorder, int[] postorder) {
|
||||
return buildTree1(inorder, 0, inorder.length, postorder, 0, postorder.length);
|
||||
}
|
||||
|
||||
public TreeNode buildTree1(int[] inorder, int inLeft, int inRight,
|
||||
int[] postorder, int postLeft, int postRight) {
|
||||
// 没有元素了
|
||||
if (inRight - inLeft < 1) {
|
||||
return null;
|
||||
}
|
||||
// 只有一个元素了
|
||||
if (inRight - inLeft == 1) {
|
||||
return new TreeNode(inorder[inLeft]);
|
||||
}
|
||||
// 后序数组postorder里最后一个即为根结点
|
||||
int rootVal = postorder[postRight - 1];
|
||||
TreeNode root = new TreeNode(rootVal);
|
||||
int rootIndex = 0;
|
||||
// 根据根结点的值找到该值在中序数组inorder里的位置
|
||||
for (int i = inLeft; i < inRight; i++) {
|
||||
if (inorder[i] == rootVal) {
|
||||
rootIndex = i;
|
||||
}
|
||||
}
|
||||
// 根据rootIndex划分左右子树
|
||||
root.left = buildTree1(inorder, inLeft, rootIndex,
|
||||
postorder, postLeft, postLeft + (rootIndex - inLeft));
|
||||
root.right = buildTree1(inorder, rootIndex + 1, inRight,
|
||||
postorder, postLeft + (rootIndex - inLeft), postRight - 1);
|
||||
return root;
|
||||
}
|
||||
}
|
||||
```
|
||||
|
||||
Python:
|
||||
|
||||
|
Reference in New Issue
Block a user