From 96e9fcb3adc8676fd6ea0671d0ddbb7d9291eaeb Mon Sep 17 00:00:00 2001 From: jiyongchao Date: Sun, 31 Mar 2024 11:19:54 +0800 Subject: [PATCH] =?UTF-8?q?Update=200017.=E7=94=B5=E8=AF=9D=E5=8F=B7?= =?UTF-8?q?=E7=A0=81=E7=9A=84=E5=AD=97=E6=AF=8D=E7=BB=84=E5=90=88.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- problems/0017.电话号码的字母组合.md | 4 ++-- 1 file changed, 2 insertions(+), 2 deletions(-) diff --git a/problems/0017.电话号码的字母组合.md b/problems/0017.电话号码的字母组合.md index cbd99f8d..0ad26bfd 100644 --- a/problems/0017.电话号码的字母组合.md +++ b/problems/0017.电话号码的字母组合.md @@ -260,7 +260,7 @@ class Solution { } - //每次迭代获取一个字符串,所以会设计大量的字符串拼接,所以这里选择更为高效的 StringBuilder + //每次迭代获取一个字符串,所以会涉及大量的字符串拼接,所以这里选择更为高效的 StringBuilder StringBuilder temp = new StringBuilder(); //比如digits如果为"23",num 为0,则str表示2对应的 abc @@ -274,7 +274,7 @@ class Solution { String str = numString[digits.charAt(num) - '0']; for (int i = 0; i < str.length(); i++) { temp.append(str.charAt(i)); - //c + //递归,处理下一层 backTracking(digits, numString, num + 1); //剔除末尾的继续尝试 temp.deleteCharAt(temp.length() - 1);