From 957c60dbfb02a6262d8e2eaa50539a4080acdc5f Mon Sep 17 00:00:00 2001
From: Charlie Yang <104724079+sxdtywm@users.noreply.github.com>
Date: Sat, 27 Jul 2024 12:12:46 +0800
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Update 0100.岛屿的最大面积.md of php and go
---
 .../kamacoder/0100.岛屿的最大面积.md   | 125 ++++++++++++++++++
 1 file changed, 125 insertions(+)

diff --git a/problems/kamacoder/0100.岛屿的最大面积.md b/problems/kamacoder/0100.岛屿的最大面积.md
index 024e509f..ea62edc2 100644
--- a/problems/kamacoder/0100.岛屿的最大面积.md
+++ b/problems/kamacoder/0100.岛屿的最大面积.md
@@ -322,6 +322,72 @@ print(result)
 
 ### Go
 
+``` go
+
+package main
+
+import (
+	"fmt"
+)
+
+var count int
+var dir = [][]int{{0, 1}, {1, 0}, {-1, 0}, {0, -1}} // 四个方向
+
+func dfs(grid [][]int, visited [][]bool, x, y int) {
+	for i := 0; i < 4; i++ {
+		nextx := x + dir[i][0]
+		nexty := y + dir[i][1]
+		if nextx < 0 || nextx >= len(grid) || nexty < 0 || nexty >= len(grid[0]) {
+			continue // 越界了，直接跳过
+		}
+		if !visited[nextx][nexty] && grid[nextx][nexty] == 1 { // 没有访问过的 同时 是陆地的
+			visited[nextx][nexty] = true
+			count++
+			dfs(grid, visited, nextx, nexty)
+		}
+	}
+}
+
+func main() {
+	var n, m int
+	fmt.Scan(&n, &m)
+
+	grid := make([][]int, n)
+	for i := 0; i < n; i++ {
+		grid[i] = make([]int, m)
+		for j := 0; j < m; j++ {
+			fmt.Scan(&grid[i][j])
+		}
+	}
+
+	visited := make([][]bool, n)
+	for i := 0; i < n; i++ {
+		visited[i] = make([]bool, m)
+	}
+
+	result := 0
+	for i := 0; i < n; i++ {
+		for j := 0; j < m; j++ {
+			if !visited[i][j] && grid[i][j] == 1 {
+				count = 1 // 因为dfs处理下一个节点，所以这里遇到陆地了就先计数，dfs处理接下来的相邻陆地
+				visited[i][j] = true
+				dfs(grid, visited, i, j)
+				if count > result {
+					result = count
+				}
+			}
+		}
+	}
+
+	fmt.Println(result)
+}
+
+
+
+```
+
+
+
 ### Rust
 
 ### Javascript
@@ -420,6 +486,65 @@ const bfs = (graph, visited, x, y) => {
 
 ### PhP
 
+``` php
+
+<?php
+
+function dfs(&$grid, &$visited, $x, $y, &$count, &$dir) {
+    for ($i = 0; $i < 4; $i++) {
+        $nextx = $x + $dir[$i][0];
+        $nexty = $y + $dir[$i][1];
+        if ($nextx < 0 || $nextx >= count($grid) || $nexty < 0 || $nexty >= count($grid[0])) continue;  // 越界了，直接跳过
+        if (!$visited[$nextx][$nexty] && $grid[$nextx][$nexty] == 1) { // 没有访问过的 同时 是陆地的
+            $visited[$nextx][$nexty] = true;
+            $count++;
+            dfs($grid, $visited, $nextx, $nexty, $count, $dir);
+        }
+    }
+}
+
+// Main function
+function main() {
+    $input = trim(fgets(STDIN));
+    list($n, $m) = explode(' ', $input);
+    
+    $grid = [];
+    for ($i = 0; $i < $n; $i++) {
+        $input = trim(fgets(STDIN));
+        $grid[] = array_map('intval', explode(' ', $input));
+    }
+    
+    $visited = [];
+    for ($i = 0; $i < $n; $i++) {
+        $visited[] = array_fill(0, $m, false);
+    }
+    
+    $result = 0;
+    $count = 0;
+    $dir = [[0, 1], [1, 0], [-1, 0], [0, -1]]; // 四个方向
+
+    for ($i = 0; $i < $n; $i++) {
+        for ($j = 0; $j < $m; $j++) {
+            if (!$visited[$i][$j] && $grid[$i][$j] == 1) {
+                $count = 1;  // 因为dfs处理下一个节点，所以这里遇到陆地了就先计数，dfs处理接下来的相邻陆地
+                $visited[$i][$j] = true;
+                dfs($grid, $visited, $i, $j, $count, $dir); // 将与其链接的陆地都标记上 true
+                $result = max($result, $count);
+            }
+        }
+    }
+    
+    echo $result . "\n";
+}
+
+main();
+
+?>
+
+
+```
+
+
 ### Swift
 
 ### Scala