diff --git a/problems/0084.柱状图中最大的矩形.md b/problems/0084.柱状图中最大的矩形.md index a0f06e8f..57df4161 100644 --- a/problems/0084.柱状图中最大的矩形.md +++ b/problems/0084.柱状图中最大的矩形.md @@ -228,6 +228,50 @@ class Solution { } ``` +单调栈 +```java +class Solution { + int largestRectangleArea(int[] heights) { + Stack st = new Stack(); + + // 数组扩容,在头和尾各加入一个元素 + int [] newHeights = new int[heights.length + 2]; + newHeights[0] = 0; + newHeights[newHeights.length - 1] = 0; + for (int index = 0; index < heights.length; index++){ + newHeights[index + 1] = heights[index]; + } + + heights = newHeights; + + st.push(0); + int result = 0; + // 第一个元素已经入栈,从下表1开始 + for (int i = 1; i < heights.length; i++) { + // 注意heights[i] 是和heights[st.top()] 比较 ,st.top()是下表 + if (heights[i] > heights[st.peek()]) { + st.push(i); + } else if (heights[i] == heights[st.peek()]) { + st.pop(); // 这个可以加,可以不加,效果一样,思路不同 + st.push(i); + } else { + while (heights[i] < heights[st.peek()]) { // 注意是while + int mid = st.peek(); + st.pop(); + int left = st.peek(); + int right = i; + int w = right - left - 1; + int h = heights[mid]; + result = Math.max(result, w * h); + } + st.push(i); + } + } + return result; + } +} +``` + Python: 动态规划