diff --git a/problems/0349.两个数组的交集.md b/problems/0349.两个数组的交集.md
index 8daf5a35..26a9286d 100644
--- a/problems/0349.两个数组的交集.md
+++ b/problems/0349.两个数组的交集.md
@@ -465,6 +465,25 @@ object Solution {
 	}
 
 ```
+
+###Ruby
+```ruby
+def intersection(nums1, nums2)
+  hash = {}
+  result = {}
+
+  nums1.each do |num|
+    hash[num] = 1 if hash[num].nil?
+  end
+
+  nums2.each do |num|
+    #取nums1和nums2交集
+    result[num] = 1 if hash[num] != nil
+  end
+
+  return result.keys
+end
+```
 ## 相关题目
 
 * [350.两个数组的交集 II](https://leetcode.cn/problems/intersection-of-two-arrays-ii/)
diff --git a/problems/1002.查找常用字符.md b/problems/1002.查找常用字符.md
index 1138d7fc..57fa7dae 100644
--- a/problems/1002.查找常用字符.md
+++ b/problems/1002.查找常用字符.md
@@ -525,6 +525,54 @@ impl Solution {
 }
 ```
 
+Ruby:
+```ruby
+def common_chars(words)
+  result = []
+  #统计所有字符串里字符出现的最小频率
+  hash = {}
+  #初始化标识
+  is_first = true
+
+  words.each do |word|
+    #记录共同字符
+    chars = []
+    word.split('').each do |chr|
+      #第一个字符串初始化
+      if is_first
+        chars << chr
+      else
+        #字母之前出现过的最小次数
+        if hash[chr] != nil && hash[chr] > 0
+          hash[chr] -= 1
+          chars << chr
+        end
+      end
+    end
+
+    is_first = false
+    #清除hash，更新字符最小频率
+    hash.clear
+    chars.each do |chr|
+      if hash[chr] != nil
+        hash[chr] += 1
+      else
+        hash[chr] = 1
+      end
+    end
+  end
+
+  #字符最小频率hash转换为字符数组
+  hash.keys.each do |key|
+    for i in 0..hash[key] - 1
+      result << key
+    end
+  end
+
+  return result
+end
+```
+
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