From 84f41f6685e744b138890cf7143ed3069a02a78e Mon Sep 17 00:00:00 2001 From: Guanzhong Pan Date: Tue, 19 Apr 2022 17:00:17 +0100 Subject: [PATCH] =?UTF-8?q?=E6=B7=BB=E5=8A=A0=200135.=E5=88=86=E5=8F=91?= =?UTF-8?q?=E7=B3=96=E6=9E=9C.md=20C=E8=AF=AD=E8=A8=80=E8=A7=A3=E6=B3=95?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit --- problems/0135.分发糖果.md | 41 +++++++++++++++++++++++++++++++++++ 1 file changed, 41 insertions(+) diff --git a/problems/0135.分发糖果.md b/problems/0135.分发糖果.md index ccdabc16..27071aee 100644 --- a/problems/0135.分发糖果.md +++ b/problems/0135.分发糖果.md @@ -238,6 +238,47 @@ var candy = function(ratings) { }; ``` +### C +```c +#define max(a, b) (((a) > (b)) ? (a) : (b)) + +int *initCandyArr(int size) { + int *candyArr = (int*)malloc(sizeof(int) * size); + + int i; + for(i = 0; i < size; ++i) + candyArr[i] = 1; + + return candyArr; +} + +int candy(int* ratings, int ratingsSize){ + // 初始化数组,每个小孩开始至少有一颗糖 + int *candyArr = initCandyArr(ratingsSize); + + int i; + // 先判断右边是否比左边评分高。若是,右边孩子的糖果为左边孩子+1(candyArr[i] = candyArr[i - 1] + 1) + for(i = 1; i < ratingsSize; ++i) { + if(ratings[i] > ratings[i - 1]) + candyArr[i] = candyArr[i - 1] + 1; + } + + // 再判断左边评分是否比右边高。 + // 若是,左边孩子糖果为右边孩子糖果+1/自己所持糖果最大值。(若糖果已经比右孩子+1多,则不需要更多糖果) + // 举例:ratings为[1, 2, 3, 1]。此时评分为3的孩子在判断右边比左边大后为3,虽然它比最末尾的1(ratings[3])大,但是candyArr[3]为1。所以不必更新candyArr[2] + for(i = ratingsSize - 2; i >= 0; --i) { + if(ratings[i] > ratings[i + 1]) + candyArr[i] = max(candyArr[i], candyArr[i + 1] + 1); + } + + // 求出糖果之和 + int result = 0; + for(i = 0; i < ratingsSize; ++i) { + result += candyArr[i]; + } + return result; +} +``` -----------------------