Merge branch 'youngyangyang04:master' into master

problems/0042.接雨水.md

@@ -744,6 +744,91 @@ var trap = function(height) {
 };
 ```
 
+### TypeScript
+
+双指针法：
+
+```typescript
+function trap(height: number[]): number {
+    const length: number = height.length;
+    let resVal: number = 0;
+    for (let i = 0; i < length; i++) {
+        let leftMaxHeight: number = height[i],
+            rightMaxHeight: number = height[i];
+        let leftIndex: number = i - 1,
+            rightIndex: number = i + 1;
+        while (leftIndex >= 0) {
+            if (height[leftIndex] > leftMaxHeight)
+                leftMaxHeight = height[leftIndex];
+            leftIndex--;
+        }
+        while (rightIndex < length) {
+            if (height[rightIndex] > rightMaxHeight)
+                rightMaxHeight = height[rightIndex];
+            rightIndex++;
+        }
+        resVal += Math.min(leftMaxHeight, rightMaxHeight) - height[i];
+    }
+    return resVal;
+};
+```
+
+动态规划：
+
+```typescript
+function trap(height: number[]): number {
+    const length: number = height.length;
+    const leftMaxHeightDp: number[] = [],
+        rightMaxHeightDp: number[] = [];
+    leftMaxHeightDp[0] = height[0];
+    rightMaxHeightDp[length - 1] = height[length - 1];
+    for (let i = 1; i < length; i++) {
+        leftMaxHeightDp[i] = Math.max(height[i], leftMaxHeightDp[i - 1]);
+    }
+    for (let i = length - 2; i >= 0; i--) {
+        rightMaxHeightDp[i] = Math.max(height[i], rightMaxHeightDp[i + 1]);
+    }
+    let resVal: number = 0;
+    for (let i = 0; i < length; i++) {
+        resVal += Math.min(leftMaxHeightDp[i], rightMaxHeightDp[i]) - height[i];
+    }
+    return resVal;
+};
+```
+
+单调栈：
+
+```typescript
+function trap(height: number[]): number {
+    const length: number = height.length;
+    const stack: number[] = [];
+    stack.push(0);
+    let resVal: number = 0;
+    for (let i = 1; i < length; i++) {
+        let top = stack[stack.length - 1];
+        if (height[top] > height[i]) {
+            stack.push(i);
+        } else if (height[top] === height[i]) {
+            stack.pop();
+            stack.push(i);
+        } else {
+            while (stack.length > 0 && height[top] < height[i]) {
+                let mid = stack.pop();
+                if (stack.length > 0) {
+                    let left = stack[stack.length - 1];
+                    let h = Math.min(height[left], height[i]) - height[mid];
+                    let w = i - left - 1;
+                    resVal += h * w;
+                    top = stack[stack.length - 1];
+                }
+            }
+            stack.push(i);
+        }
+    }
+    return resVal;
+};
+```
+
 ### C:
 
 一种更简便的双指针方法：

problems/0084.柱状图中最大的矩形.md

@@ -486,5 +486,95 @@ var largestRectangleArea = function(heights) {
     return maxArea;
 };
 ```
+TypeScript：
+
+> 双指针法（会超时）：
+
+```typescript
+function largestRectangleArea(heights: number[]): number {
+    let resMax: number = 0;
+    for (let i = 0, length = heights.length; i < length; i++) {
+        // 左开右开
+        let left: number = i - 1,
+            right: number = i + 1;
+        while (left >= 0 && heights[left] >= heights[i]) {
+            left--;
+        }
+        while (right < length && heights[right] >= heights[i]) {
+            right++;
+        }
+        resMax = Math.max(resMax, heights[i] * (right - left - 1));
+    }
+    return resMax;
+};
+```
+
+> 动态规划预处理：
+
+```typescript
+function largestRectangleArea(heights: number[]): number {
+    const length: number = heights.length;
+    const leftHeightDp: number[] = [],
+        rightHeightDp: number[] = [];
+    leftHeightDp[0] = -1;
+    rightHeightDp[length - 1] = length;
+    for (let i = 1; i < length; i++) {
+        let j = i - 1;
+        while (j >= 0 && heights[i] <= heights[j]) {
+            j = leftHeightDp[j];
+        }
+        leftHeightDp[i] = j;
+    }
+    for (let i = length - 2; i >= 0; i--) {
+        let j = i + 1;
+        while (j < length && heights[i] <= heights[j]) {
+            j = rightHeightDp[j];
+        }
+        rightHeightDp[i] = j;
+    }
+    let resMax: number = 0;
+    for (let i = 0; i < length; i++) {
+        let area = heights[i] * (rightHeightDp[i] - leftHeightDp[i] - 1);
+        resMax = Math.max(resMax, area);
+    }
+    return resMax;
+};
+```
+
+> 单调栈：
+
+```typescript
+function largestRectangleArea(heights: number[]): number {
+    heights.push(0);
+    const length: number = heights.length;
+    // 栈底->栈顶：严格单调递增
+    const stack: number[] = [];
+    stack.push(0);
+    let resMax: number = 0;
+    for (let i = 1; i < length; i++) {
+        let top = stack[stack.length - 1];
+        if (heights[top] < heights[i]) {
+            stack.push(i);
+        } else if (heights[top] === heights[i]) {
+            stack.pop();
+            stack.push(i);
+        } else {
+            while (stack.length > 0 && heights[top] > heights[i]) {
+                let mid = stack.pop();
+                let left = stack.length > 0 ? stack[stack.length - 1] : -1;
+                let w = i - left - 1;
+                let h = heights[mid];
+                resMax = Math.max(resMax, w * h);
+                top = stack[stack.length - 1];
+            }
+            stack.push(i);
+        }
+    }
+    return resMax;
+};
+```
+
+
+
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

problems/0104.二叉树的最大深度.md

@@ -495,7 +495,7 @@ class solution:
 
 
 ## go 
-
+### 104.二叉树的最大深度
 ```go
 /**
  * definition for a binary tree node.
@@ -548,6 +548,8 @@ func maxdepth(root *treenode) int {
 
 ## javascript 
 
+### 104.二叉树的最大深度
+
 ```javascript
 var maxdepth = function(root) {
     if (root === null) return 0;
@@ -595,6 +597,8 @@ var maxDepth = function(root) {
 };
 ```
 
+### 559.n叉树的最大深度
+
 N叉树的最大深度  递归写法
 ```js
 var maxDepth = function(root) {
@@ -627,9 +631,9 @@ var maxDepth = function(root) {
 };
 ```
 
-## TypeScript：
+## TypeScript
 
-> 二叉树的最大深度：
+### 104.二叉树的最大深度
 
 ```typescript
 // 后续遍历（自下而上）
@@ -672,7 +676,7 @@ function maxDepth(root: TreeNode | null): number {
 };
 ```
 
-> N叉树的最大深度
+### 559.n叉树的最大深度
 
 ```typescript
 // 后续遍历（自下而上）
@@ -702,6 +706,8 @@ function maxDepth(root: TreeNode | null): number {
 
 ## C
 
+### 104.二叉树的最大深度
+
 二叉树最大深度递归
 ```c
 int maxDepth(struct TreeNode* root){
@@ -758,7 +764,8 @@ int maxDepth(struct TreeNode* root){
 
 ## Swift
 
->二叉树最大深度
+### 104.二叉树的最大深度
+
 ```swift
 // 递归 - 后序
 func maxDepth1(_ root: TreeNode?) -> Int {
@@ -797,7 +804,8 @@ func maxDepth(_ root: TreeNode?) -> Int {
 }
 ```
 
->N叉树最大深度
+### 559.n叉树的最大深度
+
 ```swift
 // 递归
 func maxDepth(_ root: Node?) -> Int {
@@ -833,5 +841,84 @@ func maxDepth1(_ root: Node?) -> Int {
 }
 ```
 
+## Scala
+
+### 104.二叉树的最大深度
+递归法:
+```scala
+object Solution {
+  def maxDepth(root: TreeNode): Int = {
+    def process(curNode: TreeNode): Int = {
+      if (curNode == null) return 0
+      // 递归左节点和右节点，返回最大的，最后+1
+      math.max(process(curNode.left), process(curNode.right)) + 1
+    }
+    // 调用递归方法，return关键字可以省略
+    process(root) 
+  }
+}
+```
+
+迭代法:
+```scala
+object Solution {
+  import scala.collection.mutable
+  def maxDepth(root: TreeNode): Int = {
+    var depth = 0
+    if (root == null) return depth
+    val queue = mutable.Queue[TreeNode]()
+    queue.enqueue(root)
+    while (!queue.isEmpty) {
+      val len = queue.size
+      for (i <- 0 until len) {
+        val curNode = queue.dequeue()
+        if (curNode.left != null) queue.enqueue(curNode.left)
+        if (curNode.right != null) queue.enqueue(curNode.right)
+      }
+      depth += 1  // 只要有层次就+=1
+    }
+    depth
+  }
+}
+```
+
+### 559.n叉树的最大深度
+
+递归法:
+```scala
+object Solution {
+  def maxDepth(root: Node): Int = {
+    if (root == null) return 0
+    var depth = 0
+    for (node <- root.children) {
+      depth = math.max(depth, maxDepth(node))
+    }
+    depth + 1
+  }
+}
+```
+
+迭代法: (层序遍历)
+```scala
+object Solution {
+  import scala.collection.mutable
+  def maxDepth(root: Node): Int = {
+    if (root == null) return 0
+    var depth = 0
+    val queue = mutable.Queue[Node]()
+    queue.enqueue(root)
+    while (!queue.isEmpty) {
+      val len = queue.size
+      depth += 1
+      for (i <- 0 until len) {
+        val curNode = queue.dequeue()
+        for (node <- curNode.children) queue.enqueue(node)
+      }
+    }
+    depth
+  }
+}
+```
+
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

problems/0111.二叉树的最小深度.md

@@ -488,6 +488,46 @@ func minDepth(_ root: TreeNode?) -> Int {
 }
 ```
 
+
+## Scala
+
+递归法:
+```scala
+object Solution {
+  def minDepth(root: TreeNode): Int = {
+    if (root == null) return 0
+    if (root.left == null && root.right != null) return 1 + minDepth(root.right)
+    if (root.left != null && root.right == null) return 1 + minDepth(root.left)
+    // 如果两侧都不为空，则取最小值，return关键字可以省略
+    1 + math.min(minDepth(root.left), minDepth(root.right))
+  }
+}
+```
+
+迭代法:
+```scala
+object Solution {
+  import scala.collection.mutable
+  def minDepth(root: TreeNode): Int = {
+    if (root == null) return 0
+    var depth = 0
+    val queue = mutable.Queue[TreeNode]()
+    queue.enqueue(root)
+    while (!queue.isEmpty) {
+      depth += 1
+      val len = queue.size
+      for (i <- 0 until len) {
+        val curNode = queue.dequeue()
+        if (curNode.left != null) queue.enqueue(curNode.left)
+        if (curNode.right != null) queue.enqueue(curNode.right)
+        if (curNode.left == null && curNode.right == null) return depth
+      }
+    }
+    depth
+  }
+}
+```
+
 rust:
 ```rust
 impl Solution {
@@ -550,6 +590,7 @@ impl Solution {
         }
         min_depth
     }
+
 ```
 
 -----------------------

problems/0496.下一个更大元素I.md

@@ -332,5 +332,36 @@ var nextGreaterElement = function (nums1, nums2) {
 };
 ```
 
+TypeScript：
+
+```typescript
+function nextGreaterElement(nums1: number[], nums2: number[]): number[] {
+    const resArr: number[] = new Array(nums1.length).fill(-1);
+    const stack: number[] = [];
+    const helperMap: Map<number, number> = new Map();
+    nums1.forEach((num, index) => {
+        helperMap.set(num, index);
+    })
+    stack.push(0);
+    for (let i = 1, length = nums2.length; i < length; i++) {
+        let top = stack[stack.length - 1];
+        while (stack.length > 0 && nums2[top] < nums2[i]) {
+            let index = helperMap.get(nums2[top]);
+            if (index !== undefined) {
+                resArr[index] = nums2[i];
+            }
+            stack.pop();
+            top = stack[stack.length - 1];
+        }
+        if (helperMap.get(nums2[i]) !== undefined) {
+            stack.push(i);
+        }
+    }
+    return resArr;
+};
+```
+
+
+
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

problems/0503.下一个更大元素II.md

@@ -182,5 +182,31 @@ var nextGreaterElements = function (nums) {
   return res;
 };
 ```
+TypeScript：
+
+```typescript
+function nextGreaterElements(nums: number[]): number[] {
+    const length: number = nums.length;
+    const stack: number[] = [];
+    stack.push(0);
+    const resArr: number[] = new Array(length).fill(-1);
+    for (let i = 1; i < length * 2; i++) {
+        const index = i % length;
+        let top = stack[stack.length - 1];
+        while (stack.length > 0 && nums[top] < nums[index]) {
+            resArr[top] = nums[index];
+            stack.pop();
+            top = stack[stack.length - 1];
+        }
+        if (i < length) {
+            stack.push(i);
+        }
+    }
+    return resArr;
+};
+```
+
+
+
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

problems/0516.最长回文子序列.md

@@ -235,6 +235,35 @@ const longestPalindromeSubseq = (s) => {
 };
 ```
 
+TypeScript：
+
+```typescript
+function longestPalindromeSubseq(s: string): number {
+    /**
+        dp[i][j]：[i,j]区间内，最长回文子序列的长度 
+     */
+    const length: number = s.length;
+    const dp: number[][] = new Array(length).fill(0)
+        .map(_ => new Array(length).fill(0));
+    for (let i = 0; i < length; i++) {
+        dp[i][i] = 1;
+    }
+    // 自下而上，自左往右遍历
+    for (let i = length - 1; i >= 0; i--) {
+        for (let j = i + 1; j < length; j++) {
+            if (s[i] === s[j]) {
+                dp[i][j] = dp[i + 1][j - 1] + 2;
+            } else {
+                dp[i][j] = Math.max(dp[i][j - 1], dp[i + 1][j]);
+            }
+        }
+    }
+    return dp[0][length - 1];
+};
+```
+
+
+
 
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>

problems/0739.每日温度.md

@@ -372,6 +372,32 @@ var dailyTemperatures = function(temperatures) {
 };
 ```
 
+TypeScript:
+
+> 精简版：
+
+```typescript
+function dailyTemperatures(temperatures: number[]): number[] {
+    const length: number = temperatures.length;
+    const stack: number[] = [];
+    const resArr: number[] = new Array(length).fill(0);
+    stack.push(0);
+    for (let i = 1; i < length; i++) {
+        let top = stack[stack.length - 1];
+        while (
+            stack.length > 0 &&
+            temperatures[top] < temperatures[i]
+        ) {
+            resArr[top] = i - top;
+            stack.pop();
+            top = stack[stack.length - 1];
+        }
+        stack.push(i);
+    }
+    return resArr;
+};
+```
+