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Merge pull request #2415 from Chenxue3/master
Update 0513.找树左下角的值.md/0104.二叉树的最大深度.md/0112.路径总和.md
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@ -1033,6 +1033,9 @@ impl Solution {
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}
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```
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### C#
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0104.二叉树的最大深度
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```csharp
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// 递归法
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public int MaxDepth(TreeNode root) {
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@ -1088,7 +1091,76 @@ public int MaxDepth(TreeNode root)
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}
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```
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559.n叉树的最大深度
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递归法
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```csharp
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/*
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递归法
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*/
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public class Solution {
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public int MaxDepth(Node root) {
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int res = 0;
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/* 终止条件 */
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if(root == null){
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return 0;
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}
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/* logic */
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// 遍历当前节点的子节点
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for (int i = 0; i < root.children.Count; i++)
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{
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res = Math.Max(res, MaxDepth(root.children[i]));
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}
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return res + 1;
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}
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}
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// @lc code=end
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```
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迭代法(层序遍历)
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```csharp
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/*
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迭代法
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*/
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public class Solution
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{
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public int MaxDepth(Node root)
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{
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Queue<Node> que = new Queue<Node>(); // 使用泛型队列存储节点
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int res = 0;
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if(root != null){
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que.Enqueue(root); // 将根节点加入队列
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}
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while (que.Count > 0)
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{
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int size = que.Count; // 获取当前层的节点数
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res++; // 深度加一
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for (int i = 0; i < size; i++)
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{
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// 每一层的遍历
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var curNode = que.Dequeue(); // 取出队列中的节点
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for (int j = 0; j < curNode.children.Count; j++)
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{
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if (curNode.children[j] != null)
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{
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que.Enqueue(curNode.children[j]); // 将子节点加入队列
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}
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}
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}
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}
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return res; // 返回树的最大深度
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}
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}
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```
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
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</a>
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@ -1523,8 +1523,64 @@ public bool HasPathSum(TreeNode root, int targetSum)
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return HasPathSum(root.left, targetSum - root.val) || HasPathSum(root.right, targetSum - root.val);
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}
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```
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0113.路径总和:
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```csharp
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/*
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* @lc app=leetcode id=113 lang=csharp
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* 0113.路径总和 II
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* [113] Path Sum II
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* 递归法
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*/
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public class Solution {
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private List<List<int>> result = new List<List<int>>();
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private List<int> path = new List<int>();
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// Main function to find paths with the given sum
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public IList<IList<int>> PathSum(TreeNode root, int targetSum) {
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result.Clear();
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path.Clear();
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if (root == null) return result.Select(list => list as IList<int>).ToList();
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path.Add(root.val); // Add the root node to the path
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traversal(root, targetSum - root.val); // Start the traversal
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return result.Select(list => list as IList<int>).ToList();
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}
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// Recursive function to traverse the tree and find paths
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private void traversal(TreeNode node, int count) {
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// If a leaf node is reached and the target sum is achieved
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if (node.left == null && node.right == null && count == 0) {
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result.Add(new List<int>(path)); // Add a copy of the path to the result
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return;
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}
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// If a leaf node is reached and the target sum is not achieved, or if it's not a leaf node
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if (node.left == null && node.right == null) return;
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// Traverse the left subtree
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if (node.left != null) {
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path.Add(node.left.val);
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count -= node.left.val;
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traversal(node.left, count); // Recursive call
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count += node.left.val; // Backtrack
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path.RemoveAt(path.Count - 1); // Backtrack
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}
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// Traverse the right subtree
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if (node.right != null) {
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path.Add(node.right.val);
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count -= node.right.val;
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traversal(node.right, count); // Recursive call
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count += node.right.val; // Backtrack
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path.RemoveAt(path.Count - 1); // Backtrack
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}
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}
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}
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// @lc code=end
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```
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
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</a>
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@ -716,9 +716,55 @@ public void Traversal(TreeNode root, int depth)
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return;
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}
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```
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```csharp
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/*
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* @lc app=leetcode id=513 lang=csharp
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* 迭代法
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* [513] Find Bottom Left Tree Value
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*/
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// @lc code=start
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public class Solution
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{
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public int FindBottomLeftValue(TreeNode root)
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{
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Queue<TreeNode> que = new Queue<TreeNode>();
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if (root != null)
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{
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que.Enqueue(root);
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}
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int ans = 0;
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while (que.Count != 0)
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{
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int size = que.Count;
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for (var i = 0; i < size; i++)
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{
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var curNode = que.Peek();
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que.Dequeue();
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if(i == 0){
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ans = curNode.val;
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}
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if (curNode.left != null)
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{
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que.Enqueue(curNode.left);
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}
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if (curNode.right != null)
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{
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que.Enqueue(curNode.right);
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}
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}
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}
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return ans;
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}
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}
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// @lc code=end
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```
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
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</a>
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