添加（0459.重复的子字符串.md）：增加typescript版本

problems/0459.重复的子字符串.md

@@ -361,7 +361,65 @@ var repeatedSubstringPattern = function (s) {
 };
 ```
 
+TypeScript:
 
+> 前缀表统一减一
+
+```typescript
+function repeatedSubstringPattern(s: string): boolean {
+    function getNext(str: string): number[] {
+        let next: number[] = [];
+        let j: number = -1;
+        next[0] = j;
+        for (let i = 1, length = str.length; i < length; i++) {
+            while (j >= 0 && str[i] !== str[j + 1]) {
+                j = next[j];
+            }
+            if (str[i] === str[j + 1]) {
+                j++;
+            }
+            next[i] = j;
+        }
+        return next;
+    }
+
+    let next: number[] = getNext(s);
+    let sLength: number = s.length;
+    let nextLength: number = next.length;
+    let suffixLength: number = next[nextLength - 1] + 1;
+    if (suffixLength > 0 && sLength % (sLength - suffixLength) === 0) return true;
+    return false;
+};
+```
+
+> 前缀表不减一
+
+```typescript
+function repeatedSubstringPattern(s: string): boolean {
+    function getNext(str: string): number[] {
+        let next: number[] = [];
+        let j: number = 0;
+        next[0] = j;
+        for (let i = 1, length = str.length; i < length; i++) {
+            while (j > 0 && str[i] !== str[j]) {
+                j = next[j - 1];
+            }
+            if (str[i] === str[j]) {
+                j++;
+            }
+            next[i] = j;
+        }
+        return next;
+    }
+
+    let next: number[] = getNext(s);
+    let sLength: number = s.length;
+    let nextLength: number = next.length;
+    let suffixLength: number = next[nextLength - 1];
+    if (suffixLength > 0 && sLength % (sLength - suffixLength) === 0) return true;
+    return false;
+};
+```
 
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