From 7a0d134d6e96541deb2fe4757743aed4c3ecd94e Mon Sep 17 00:00:00 2001
From: Baturu <45113401+z80160280@users.noreply.github.com>
Date: Mon, 31 May 2021 18:31:10 -0700
Subject: [PATCH] =?UTF-8?q?Update=200242.=E6=9C=89=E6=95=88=E7=9A=84?=
 =?UTF-8?q?=E5=AD=97=E6=AF=8D=E5=BC=82=E4=BD=8D=E8=AF=8D.md?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 problems/0242.有效的字母异位词.md | 17 ++++++++++++++++-
 1 file changed, 16 insertions(+), 1 deletion(-)

diff --git a/problems/0242.有效的字母异位词.md b/problems/0242.有效的字母异位词.md
index 6a6faf63..ba942f70 100644
--- a/problems/0242.有效的字母异位词.md
+++ b/problems/0242.有效的字母异位词.md
@@ -113,7 +113,22 @@ class Solution {
 ```
 
 Python：
-
+```python
+class Solution:
+    def isAnagram(self, s: str, t: str) -> bool:
+        record = [0] * 26
+        for i in range(len(s)):
+            #并不需要记住字符a的ASCII，只要求出一个相对数值就可以了
+            record[ord(s[i]) - ord("a")] += 1
+        print(record)
+        for i in range(len(t)):
+            record[ord(t[i]) - ord("a")] -= 1
+        for i in range(26):
+            if record[i] != 0:
+                #record数组如果有的元素不为零0，说明字符串s和t 一定是谁多了字符或者谁少了字符。
+                return False
+        return True
+```
 
 Go：
 ```go