From 78efc0ab870f97f015a7babefad86092624889aa Mon Sep 17 00:00:00 2001
From: Luo <82520819+Jerry-306@users.noreply.github.com>
Date: Mon, 4 Oct 2021 09:55:01 +0800
Subject: [PATCH] =?UTF-8?q?=E7=BA=A0=E6=AD=A3=200279=20=E5=AE=8C=E5=85=A8?=
 =?UTF-8?q?=E5=B9=B3=E6=96=B9=E6=95=B0=20JavaScript=E7=89=88=E6=9C=AC?=
 =?UTF-8?q?=E4=BB=A3=E7=A0=81=E9=94=99=E8=AF=AF?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

首先 0 不是题目中所说的完全平方数，所有 i 的范围应该从 1 开始；
其次，i <= n 不太合理，增加了大量无用计算，应改成 i**2 （即 i^2）<= n 更为合适
---
 problems/0279.完全平方数.md | 4 ++--
 1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/problems/0279.完全平方数.md b/problems/0279.完全平方数.md
index a00ed47e..b1af7e95 100644
--- a/problems/0279.完全平方数.md
+++ b/problems/0279.完全平方数.md
@@ -334,8 +334,8 @@ var numSquares1 = function(n) {
     let dp = new Array(n + 1).fill(Infinity)
     dp[0] = 0
 
-    for(let i = 0; i <= n; i++) {
-        let val = i * i
+    for(let i = 1; i**2 <= n; i++) {
+        let val = i**2
         for(let j = val; j <= n; j++) {
             dp[j] = Math.min(dp[j], dp[j - val] + 1)
         }