From 78c6602ff20c309132007795956f332d66ff7130 Mon Sep 17 00:00:00 2001
From: ZongqinWang <1722249371@qq.com>
Date: Fri, 13 May 2022 10:05:27 +0800
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---
 problems/0349.两个数组的交集.md | 42 ++++++++++++++++++++++++++
 1 file changed, 42 insertions(+)

diff --git a/problems/0349.两个数组的交集.md b/problems/0349.两个数组的交集.md
index 45f19b6e..49cf4112 100644
--- a/problems/0349.两个数组的交集.md
+++ b/problems/0349.两个数组的交集.md
@@ -312,7 +312,49 @@ int* intersection1(int* nums1, int nums1Size, int* nums2, int nums2Size, int* re
     return result;
 }
 ```
+Scala:
 
+正常解法:
+```scala
+object Solution {
+  def intersection(nums1: Array[Int], nums2: Array[Int]): Array[Int] = {
+    // 导入mutable
+    import scala.collection.mutable
+    // 临时Set，用于记录数组1出现的每个元素
+    val tmpSet: mutable.HashSet[Int] = new mutable.HashSet[Int]()
+    // 结果Set，存储最终结果
+    val resSet: mutable.HashSet[Int] = new mutable.HashSet[Int]()
+    // 遍历nums1，把每个元素添加到tmpSet
+    nums1.foreach(tmpSet.add(_))
+    // 遍历nums2，如果在tmpSet存在就添加到resSet
+    nums2.foreach(elem => {
+      if (tmpSet.contains(elem)) {
+        resSet.add(elem)
+      }
+    })
+    // 将结果转换为Array返回，return可以省略
+    resSet.toArray
+  }
+}
+```
+骚操作1:
+```scala
+object Solution {
+  def intersection(nums1: Array[Int], nums2: Array[Int]): Array[Int] = {
+    // 先转为Set，然后取交集，最后转换为Array
+    (nums1.toSet).intersect(nums2.toSet).toArray
+  }
+}
+```
+骚操作2:
+```scala
+object Solution {
+  def intersection(nums1: Array[Int], nums2: Array[Int]): Array[Int] = {
+    // distinct去重，然后取交集
+    (nums1.distinct).intersect(nums2.distinct)
+  }
+}
+```
 ## 相关题目
 
 * 350.两个数组的交集 II