diff --git a/problems/1002.查找常用字符.md b/problems/1002.查找常用字符.md
index 36937b0b..075b5ef1 100644
--- a/problems/1002.查找常用字符.md
+++ b/problems/1002.查找常用字符.md
@@ -418,6 +418,38 @@ char ** commonChars(char ** words, int wordsSize, int* returnSize){
     return ret;
 }
 ```
-
+Scala:
+```scala
+object Solution {
+  def commonChars(words: Array[String]): List[String] = {
+    // 声明返回结果的不可变List集合，因为res要重新赋值，所以声明为var
+    var res = List[String]()
+    var hash = new Array[Int](26) // 统计字符出现的最小频率
+    // 统计第一个字符串中字符出现的次数
+    for (i <- 0 until words(0).length) {
+      hash(words(0)(i) - 'a') += 1
+    }
+    // 统计其他字符串出现的频率
+    for (i <- 1 until words.length) {
+      // 统计其他字符出现的频率
+      var hashOtherStr = new Array[Int](26)
+      for (j <- 0 until words(i).length) {
+        hashOtherStr(words(i)(j) - 'a') += 1
+      }
+      // 更新hash，取26个字母最小出现的频率
+      for (k <- 0 until 26) {
+        hash(k) = math.min(hash(k), hashOtherStr(k))
+      }
+    }
+    // 根据hash的结果转换输出的形式
+    for (i <- 0 until 26) {
+      for (j <- 0 until hash(i)) {
+        res = res :+ (i + 'a').toChar.toString
+      }
+    }
+    res
+  }
+}
+```
 -----------------------
 <div align="center"><img src=https://code-thinking.cdn.bcebos.com/pics/01二维码一.jpg width=500> </img></div>