From 6e88b2034d70d261a9cd0388cdcf906e50677195 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E7=A8=8B=E5=BA=8F=E5=91=98Carl?= <sunxiuyang04@gmail.com>
Date: Sun, 7 May 2023 09:54:15 +0800
Subject: [PATCH] =?UTF-8?q?Update=200242.=E6=9C=89=E6=95=88=E7=9A=84?=
 =?UTF-8?q?=E5=AD=97=E6=AF=8D=E5=BC=82=E4=BD=8D=E8=AF=8D.md?=
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---
 problems/0242.有效的字母异位词.md | 24 +++++++++++++++++++++++
 1 file changed, 24 insertions(+)

diff --git a/problems/0242.有效的字母异位词.md b/problems/0242.有效的字母异位词.md
index 3f4b00dc..09674ecd 100644
--- a/problems/0242.有效的字母异位词.md
+++ b/problems/0242.有效的字母异位词.md
@@ -138,7 +138,31 @@ class Solution:
                 return False
         return True
 ```
+Python写法二（没有使用数组作为哈希表，只是介绍defaultdict这样一种解题思路）：
 
+```python
+class Solution:
+    def isAnagram(self, s: str, t: str) -> bool:
+        from collections import defaultdict
+        
+        s_dict = defaultdict(int)
+        t_dict = defaultdict(int)
+        for x in s:
+            s_dict[x] += 1
+        
+        for x in t:
+            t_dict[x] += 1
+        return s_dict == t_dict
+```
+Python写法三(没有使用数组作为哈希表，只是介绍Counter这种更方便的解题思路)：
+
+```python
+class Solution(object):
+    def isAnagram(self, s: str, t: str) -> bool:
+        from collections import Counter
+        a_count = Counter(s)
+        b_count = Counter(t)
+        return a_count == b_count
 
 Go：