From d874aaa2dd12685f54aba09201903319aa3bd183 Mon Sep 17 00:00:00 2001
From: Asterisk <44215173+casnz1601@users.noreply.github.com>
Date: Sun, 16 Oct 2022 20:19:40 -0400
Subject: [PATCH] =?UTF-8?q?Update=200001.=E4=B8=A4=E6=95=B0=E4=B9=8B?=
 =?UTF-8?q?=E5=92=8C.md?=
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替代造成逻辑误导旧python代码
---
 problems/0001.两数之和.md | 24 +++++-------------------
 1 file changed, 5 insertions(+), 19 deletions(-)

diff --git a/problems/0001.两数之和.md b/problems/0001.两数之和.md
index acf2a995..7bada9af 100644
--- a/problems/0001.两数之和.md
+++ b/problems/0001.两数之和.md
@@ -152,25 +152,11 @@ class Solution:
     def twoSum(self, nums: List[int], target: int) -> List[int]:
         records = dict()
 
-        # 用枚举更方便，就不需要通过索引再去取当前位置的值
-        for idx, val in enumerate(nums):
-            if target - val not in records:
-                records[val] = idx
-            else:
-                return [records[target - val], idx] # 如果存在就返回字典记录索引和当前索引
-```
-
-Python (v2):
-
-```python
-class Solution:
-    def twoSum(self, nums: List[int], target: int) -> List[int]:
-        rec = {}
-        for i in range(len(nums)):
-            rest = target - nums[i]
-            # Use get to get the index of the data, making use of one of the dictionary properties.
-            if rec.get(rest, None) is not None: return [rec[rest], i]
-            rec[nums[i]] = i
+        for index, value in enumerate(nums):
+            if target - value in records:
+                return [records[target- value], index]
+            records[value] = index
+        return []
 ```
 
 Go：