添加 0096.城市间货物运输III python3 SPFA版本

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swjtuhjf
2024-11-12 14:04:38 +08:00
parent 4ddbb265e4
commit 6c497c692b

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@ -703,6 +703,9 @@ public class Main {
``` ```
### Python ### Python
Bellman-Ford方法求解单源有限最短路
```python ```python
def main(): def main():
# 輸入 # 輸入
@ -736,6 +739,48 @@ def main():
if __name__ == "__main__":
main()
```
SPFA方法求解单源有限最短路
```python
from collections import deque
from math import inf
def main():
n, m = [int(i) for i in input().split()]
graph = [[] for _ in range(n+1)]
for _ in range(m):
v1, v2, val = [int(i) for i in input().split()]
graph[v1].append([v2, val])
src, dst, k = [int(i) for i in input().split()]
min_dist = [inf for _ in range(n+1)]
min_dist[src] = 0 # 初始化起点的距离
que = deque([src])
while k != -1 and que:
visited = [False for _ in range(n+1)] # 用于保证每次松弛时一个节点最多加入队列一次
que_size = len(que)
temp_dist = min_dist.copy() # 用于记录上一次遍历的结果
for _ in range(que_size):
cur_node = que.popleft()
for next_node, val in graph[cur_node]:
if min_dist[next_node] > temp_dist[cur_node] + val:
min_dist[next_node] = temp_dist[cur_node] + val
if not visited[next_node]:
que.append(next_node)
visited[next_node] = True
k -= 1
if min_dist[dst] == inf:
print("unreachable")
else:
print(min_dist[dst])
if __name__ == "__main__": if __name__ == "__main__":
main() main()
``` ```