From 15e3377491590fceee2af002803183bd6f15e236 Mon Sep 17 00:00:00 2001
From: re1own <595875338@qq.com>
Date: Fri, 30 Dec 2022 01:42:47 -0500
Subject: [PATCH] =?UTF-8?q?Update=200518.=E9=9B=B6=E9=92=B1=E5=85=91?=
 =?UTF-8?q?=E6=8D=A2II.md=20=E5=AF=B9dp[0]=3D1=E7=9A=84=E8=A1=A5=E5=85=85?=
 =?UTF-8?q?=E8=A7=A3=E9=87=8A?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

---
 .DS_Store                       | Bin 0 -> 6148 bytes
 problems/.DS_Store              | Bin 0 -> 6148 bytes
 problems/0518.零钱兑换II.md |   3 +++
 3 files changed, 3 insertions(+)
 create mode 100644 .DS_Store
 create mode 100644 problems/.DS_Store

diff --git a/.DS_Store b/.DS_Store
new file mode 100644
index 0000000000000000000000000000000000000000..da03c1c1b207c3ee04079084ecb15dcfff97ef95
GIT binary patch
literal 6148
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W5N(68M)aW2kAR|q8e-r_8F&SXo^XBu

literal 0
HcmV?d00001

diff --git a/problems/.DS_Store b/problems/.DS_Store
new file mode 100644
index 0000000000000000000000000000000000000000..32266f382acd7b944a23d2f5f05301bbed6d4e0f
GIT binary patch
literal 6148
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z_{%Q$|IMGz|6!3{sRF9Nzf!=&c|Y%AOVV3go8w+<;R84uud6)PC78HYjJ4c~*Wk_&
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literal 0
HcmV?d00001

diff --git a/problems/0518.零钱兑换II.md b/problems/0518.零钱兑换II.md
index 2fc807cd..f6a8044c 100644
--- a/problems/0518.零钱兑换II.md
+++ b/problems/0518.零钱兑换II.md
@@ -95,6 +95,8 @@ dp[j]  就是所有的dp[j - coins[i]]（考虑coins[i]的情况）相加。
 
 下标非0的dp[j]初始化为0，这样累计加dp[j - coins[i]]的时候才不会影响真正的dp[j]
 
+dp[0]=1还说明了一种情况：如果正好选了coins[i]后，也就是j-coins[i] == 0的情况表示这个硬币刚好能选，此时dp[0]为1表示只选coins[i]存在这样的一种选法。
+
 4. 确定遍历顺序
 
 本题中我们是外层for循环遍历物品（钱币），内层for遍历背包（金钱总额），还是外层for遍历背包（金钱总额），内层for循环遍历物品（钱币）呢？
@@ -316,3 +318,4 @@ object Solution {
 <a href="https://programmercarl.com/other/kstar.html" target="_blank">
   <img src="../pics/网站星球宣传海报.jpg" width="1000"/>
 </a>
+