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Update 背包理论基础01背包-2.md Python代码
增加python部分代码. 测试结果: ``` [[0, 15, 15, 15, 15], [0, 15, 15, 20, 35], [0, 15, 15, 20, 35]] ``` 与题解一致.
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@ -307,6 +307,41 @@ Java:
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Python:
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```python
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def test_2_wei_bag_problem1(bag_size, weight, value) -> int:
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rows, cols = len(weight), bag_size + 1
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dp = [[0 for _ in range(cols)] for _ in range(rows)]
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res = 0
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# 初始化dp数组.
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for i in range(rows):
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dp[i][0] = 0
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first_item_weight, first_item_value = weight[0], value[0]
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for j in range(1, cols):
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if first_item_weight <= j:
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dp[0][j] = first_item_value
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# 更新dp数组: 先遍历物品, 再遍历背包.
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for i in range(1, len(weight)):
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cur_weight, cur_val = weight[i], value[i]
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for j in range(1, cols):
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if cur_weight > j: # 说明背包装不下当前物品.
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dp[i][j] = dp[i - 1][j] # 所以不装当前物品.
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else:
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# 定义dp数组: dp[i][j] 前i个物品里,放进容量为j的背包,价值总和最大是多少。
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dp[i][j] = max(dp[i - 1][j], dp[i - 1][j - cur_weight]+ cur_val)
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if dp[i][j] > res:
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res = dp[i][j]
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print(dp)
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if __name__ == "__main__":
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bag_size = 4
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weight = [1, 3, 4]
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value = [15, 20, 30]
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test_2_wei_bag_problem1(bag_size, weight, value)
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```
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Go:
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