From 5fd43cfd0a5770e0cb532687766f64306b5bbfed Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E8=91=A3xx?= <dxxxue@gmail.com>
Date: Thu, 28 Apr 2022 22:20:22 +0800
Subject: [PATCH] =?UTF-8?q?0300.=E6=9C=80=E9=95=BF=E4=B8=8A=E5=8D=87?=
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---
 problems/0300.最长上升子序列.md | 33 ++++++++++++++++++++++++++
 1 file changed, 33 insertions(+)

diff --git a/problems/0300.最长上升子序列.md b/problems/0300.最长上升子序列.md
index dfdd5125..f68edb5a 100644
--- a/problems/0300.最长上升子序列.md
+++ b/problems/0300.最长上升子序列.md
@@ -168,6 +168,39 @@ func lengthOfLIS(nums []int ) int {
 }
 ```
 
+```go
+// 动态规划求解
+func lengthOfLIS(nums []int) int {
+    // dp数组的定义 dp[i]表示取第i个元素的时候，表示子序列的长度，其中包括 nums[i] 这个元素
+    dp := make([]int, len(nums))
+
+    // 初始化，所有的元素都应该初始化为1
+    for i := range dp {
+        dp[i] = 1
+    }
+
+    ans := dp[0]
+    for i := 1; i < len(nums); i++ {
+        for j := 0; j < i; j++ {
+            if nums[i] > nums[j] {
+                dp[i] = max(dp[i], dp[j] + 1)
+            }
+        }
+        if dp[i] > ans {
+            ans = dp[i]
+        }
+    }
+    return ans
+}
+
+func max(x, y int) int {
+    if x > y {
+        return x
+    }
+    return y
+}
+```
+
 Javascript
 ```javascript
 const lengthOfLIS = (nums) => {