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refactor: 0102.二叉树的层序遍历.md
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@ -692,27 +692,29 @@ func levelOrderBottom(root *TreeNode) [][]int {
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#### Javascript:
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```javascript
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var levelOrderBottom = function(root) {
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let res = [], queue = [];
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queue.push(root);
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while(queue.length && root!==null) {
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// 存放当前层级节点数组
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let curLevel = [];
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// 计算当前层级节点数量
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let length = queue.length;
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while(length--) {
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let node = queue.shift();
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// 把当前层节点存入curLevel数组
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curLevel.push(node.val);
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// 把下一层级的左右节点存入queue队列
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node.left && queue.push(node.left);
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node.right && queue.push(node.right);
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}
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// 从数组前头插入值,避免最后反转数组,减少运算时间
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res.unshift(curLevel);
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var levelOrderBottom = function (root) {
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let res = [],
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queue = [];
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queue.push(root);
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while (queue.length && root !== null) {
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// 存放当前层级节点数组
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let curLevel = [];
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// 计算当前层级节点数量
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let length = queue.length;
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while (length--) {
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let node = queue.shift();
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// 把当前层节点存入curLevel数组
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curLevel.push(node.val);
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// 把下一层级的左右节点存入queue队列
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node.left && queue.push(node.left);
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node.right && queue.push(node.right);
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}
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return res;
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// 从数组前头插入值,避免最后反转数组,减少运算时间
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res.unshift(curLevel);
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}
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return res;
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};
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```
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#### TypeScript:
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@ -71,7 +71,7 @@
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有递归的地方就有回溯,那么回溯在哪里呢?
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就地递归函数的下面,例如如下代码:
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就递归函数的下面,例如如下代码:
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```cpp
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void dfs(参数) {
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