From 57e56c508b567c453945b3398dc84c83002d6ec0 Mon Sep 17 00:00:00 2001 From: a12bb <2713204748@qq.com> Date: Tue, 12 Mar 2024 21:39:58 +0800 Subject: [PATCH] =?UTF-8?q?Update=200714.=E4=B9=B0=E5=8D=96=E8=82=A1?= =?UTF-8?q?=E7=A5=A8=E7=9A=84=E6=9C=80=E4=BD=B3=E6=97=B6=E6=9C=BA=E5=90=AB?= =?UTF-8?q?=E6=89=8B=E7=BB=AD=E8=B4=B9=EF=BC=88=E5=8A=A8=E6=80=81=E8=A7=84?= =?UTF-8?q?=E5=88=92=EF=BC=89.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit 0714.买卖股票的最佳时机含手续费新增C语言实现 --- ...佳时机含手续费（动态规划）.md | 23 +++++++++++++++++++ 1 file changed, 23 insertions(+) diff --git a/problems/0714.买卖股票的最佳时机含手续费（动态规划）.md b/problems/0714.买卖股票的最佳时机含手续费（动态规划）.md index 7e8e3d7c..88ba9271 100644 --- a/problems/0714.买卖股票的最佳时机含手续费（动态规划）.md +++ b/problems/0714.买卖股票的最佳时机含手续费（动态规划）.md @@ -247,7 +247,29 @@ function maxProfit(prices: number[], fee: number): number { }; ``` +### C: + +```c +#define max(a, b) ((a) > (b) ? (a) : (b)) + +// dp[i][0] 表示第i天持有股票所省最多现金。 +// dp[i][1] 表示第i天不持有股票所得最多现金 +int maxProfit(int* prices, int pricesSize, int fee) { + int dp[pricesSize][2]; + dp[0][0] = -prices[0]; + dp[0][1] = 0; + for (int i = 1; i < pricesSize; ++i) { + dp[i][0] = max(dp[i - 1][0], dp[i - 1][1] - prices[i]); + dp[i][1] = max(dp[i - 1][1], dp[i - 1][0] + prices[i] - fee); + } + return dp[pricesSize - 1][1]; +} +``` + + + ### Rust: + **贪心** ```Rust @@ -304,3 +326,4 @@ impl Solution { +