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Update 0063.不同路径II.md
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@ -397,7 +397,39 @@ class Solution:
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```
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动态规划(版本五)
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```python
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class Solution:
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def uniquePathsWithObstacles(self, obstacleGrid):
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if obstacleGrid[0][0] == 1:
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return 0
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m, n = len(obstacleGrid), len(obstacleGrid[0])
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dp = [0] * n # 创建一个一维列表用于存储路径数
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# 初始化第一行的路径数
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for j in range(n):
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if obstacleGrid[0][j] == 1:
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break
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dp[j] = 1
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# 计算其他行的路径数
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for i in range(1, m):
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if obstacleGrid[i][0] == 1:
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dp[0] = 0
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for j in range(1, n):
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if obstacleGrid[i][j] == 1:
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dp[j] = 0
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continue
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dp[j] += dp[j - 1]
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return dp[-1] # 返回最后一个元素,即终点的路径数
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```
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### Go
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```go
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