Update 0669.修剪二叉搜索树.md

problems/0669.修剪二叉搜索树.md

@@ -271,64 +271,72 @@ class Solution {
 
 ## Python
 
-**递归**
-
+递归法（版本一）
 ```python
-# Definition for a binary tree node.
-# class TreeNode:
-#     def __init__(self, val=0, left=None, right=None):
-#         self.val = val
-#         self.left = left
-#         self.right = right
 class Solution:
     def trimBST(self, root: TreeNode, low: int, high: int) -> TreeNode:
-        '''
-        确认递归函数参数以及返回值：返回更新后剪枝后的当前root节点
-        '''
-        # Base Case
-        if not root: return None
-
-        # 单层递归逻辑
+        if root is None:
+            return None
         if root.val < low:
-            # 若当前root节点小于左界：只考虑其右子树，用于替代更新后的其本身，抛弃其左子树整体
+            # 寻找符合区间 [low, high] 的节点
             return self.trimBST(root.right, low, high)
-
-        if high < root.val:
-            # 若当前root节点大于右界：只考虑其左子树，用于替代更新后的其本身，抛弃其右子树整体
+        if root.val > high:
+            # 寻找符合区间 [low, high] 的节点
             return self.trimBST(root.left, low, high)
-
-        if low <= root.val <= high:
-            root.left = self.trimBST(root.left, low, high)
-            root.right = self.trimBST(root.right, low, high)
-            # 返回更新后的剪枝过的当前节点root
+        root.left = self.trimBST(root.left, low, high)  # root.left 接入符合条件的左孩子
+        root.right = self.trimBST(root.right, low, high)  # root.right 接入符合条件的右孩子
         return root
+
 ```
-
-**迭代**
-
+递归法（版本二）精简
 ```python
 class Solution:
-    def trimBST(self, root: Optional[TreeNode], low: int, high: int) -> Optional[TreeNode]:
-        if not root: return root
-        # 处理头结点，让root移动到[L, R] 范围内，注意是左闭右开
-        while root and (root.val < low or root.val > high):
-            if root.val < low:  # 小于L往右走
-                root = root.right
-            else:  # 大于R往左走
-                root = root.left
-        # 此时root已经在[L, R] 范围内，处理左孩子元素小于L的情况
+    def trimBST(self, root: TreeNode, low: int, high: int) -> TreeNode:
+        if root is None:
+            return None
+        if root.val < low:
+            return self.trimBST(root.right, low, high)
+        if root.val > high:
+            return self.trimBST(root.left, low, high)
+        root.left = self.trimBST(root.left, low, high)
+        root.right = self.trimBST(root.right, low, high)
+        return root
+
+
+```
+
+迭代法
+```python
+class Solution:
+    def trimBST(self, root: TreeNode, L: int, R: int) -> TreeNode:
+        if not root:
+            return None
+        
+        # 处理头结点，让root移动到[L, R] 范围内，注意是左闭右闭
+        while root and (root.val < L or root.val > R):
+            if root.val < L:
+                root = root.right  # 小于L往右走
+            else:
+                root = root.left  # 大于R往左走
+        
         cur = root
+        
+        # 此时root已经在[L, R] 范围内，处理左孩子元素小于L的情况
         while cur:
-            while cur.left and cur.left.val < low:
+            while cur.left and cur.left.val < L:
                 cur.left = cur.left.right
             cur = cur.left
-        # 此时root已经在[L, R] 范围内，处理右孩子大于R的情况
+        
         cur = root
+        
+        # 此时root已经在[L, R] 范围内，处理右孩子大于R的情况
         while cur:
-            while cur.right and cur.right.val > high:
+            while cur.right and cur.right.val > R:
                 cur.right = cur.right.left
             cur = cur.right
+        
         return root
+
 ```
 
 ## Go