From 4261d96a144c91ba577a1a2c3bdad5fb7ce38696 Mon Sep 17 00:00:00 2001 From: roylx <73628821+roylx@users.noreply.github.com> Date: Tue, 15 Nov 2022 10:27:03 -0700 Subject: [PATCH] =?UTF-8?q?Update=200714.=E4=B9=B0=E5=8D=96=E8=82=A1?= =?UTF-8?q?=E7=A5=A8=E7=9A=84=E6=9C=80=E4=BD=B3=E6=97=B6=E6=9C=BA=E5=90=AB?= =?UTF-8?q?=E6=89=8B=E7=BB=AD=E8=B4=B9.md?= MIME-Version: 1.0 Content-Type: text/plain; charset=UTF-8 Content-Transfer-Encoding: 8bit 更新Python贪心,更容易理解 --- .../0714.买卖股票的最佳时机含手续费.md | 10 +++++----- 1 file changed, 5 insertions(+), 5 deletions(-) diff --git a/problems/0714.买卖股票的最佳时机含手续费.md b/problems/0714.买卖股票的最佳时机含手续费.md index 66fb9fb6..faa56d42 100644 --- a/problems/0714.买卖股票的最佳时机含手续费.md +++ b/problems/0714.买卖股票的最佳时机含手续费.md @@ -206,13 +206,13 @@ class Solution: # 贪心思路 result = 0 minPrice = prices[0] for i in range(1, len(prices)): - if prices[i] < minPrice: + if prices[i] < minPrice: # 此时有更低的价格,可以买入 minPrice = prices[i] - elif prices[i] >= minPrice and prices[i] <= minPrice + fee: - continue - else: - result += prices[i] - minPrice - fee + elif prices[i] > (minPrice + fee): # 此时有利润,同时假买入高价的股票,看看是否继续盈利 + result += prices[i] - (minPrice + fee) minPrice = prices[i] - fee + else: # minPrice<= prices[i] <= minPrice + fee, 价格处于minPrice和minPrice+fee之间,不做操作 + continue return result ```