From 4261d96a144c91ba577a1a2c3bdad5fb7ce38696 Mon Sep 17 00:00:00 2001
From: roylx <73628821+roylx@users.noreply.github.com>
Date: Tue, 15 Nov 2022 10:27:03 -0700
Subject: [PATCH] =?UTF-8?q?Update=200714.=E4=B9=B0=E5=8D=96=E8=82=A1?=
 =?UTF-8?q?=E7=A5=A8=E7=9A=84=E6=9C=80=E4=BD=B3=E6=97=B6=E6=9C=BA=E5=90=AB?=
 =?UTF-8?q?=E6=89=8B=E7=BB=AD=E8=B4=B9.md?=
MIME-Version: 1.0
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit

更新Python贪心，更容易理解
---
 .../0714.买卖股票的最佳时机含手续费.md    | 10 +++++-----
 1 file changed, 5 insertions(+), 5 deletions(-)

diff --git a/problems/0714.买卖股票的最佳时机含手续费.md b/problems/0714.买卖股票的最佳时机含手续费.md
index 66fb9fb6..faa56d42 100644
--- a/problems/0714.买卖股票的最佳时机含手续费.md
+++ b/problems/0714.买卖股票的最佳时机含手续费.md
@@ -206,13 +206,13 @@ class Solution: # 贪心思路
         result = 0
         minPrice = prices[0]
         for i in range(1, len(prices)):
-            if prices[i] < minPrice:
+            if prices[i] < minPrice: # 此时有更低的价格，可以买入
                 minPrice = prices[i]
-            elif prices[i] >= minPrice and prices[i] <= minPrice + fee: 
-                continue
-            else: 
-                result += prices[i] - minPrice - fee
+            elif prices[i] > (minPrice + fee): # 此时有利润，同时假买入高价的股票，看看是否继续盈利
+                result += prices[i] - (minPrice + fee)
                 minPrice = prices[i] - fee
+            else: # minPrice<= prices[i] <= minPrice + fee， 价格处于minPrice和minPrice+fee之间，不做操作
+                continue
         return result
 ```