Update 0242.有效的字母异位词.md

problems/0242.有效的字母异位词.md

@@ -122,21 +122,7 @@ class Solution {
 ```
 
 Python：
-(版本一) 使用数组
+
-```python
-class Solution:
-    def isAnagram(self, s: str, t: str) -> bool:
-        record = [0] * 26
-        for i in range(len(s)):
-            record[ord(s[i]) - ord("a")] += 1
-        for i in range(len(t)):
-            record[ord(t[i]) - ord("a")] -= 1
-        for i in range(26):
-            if record[i] != 0:
-                return False
-        return True
-```
-(版本二) 使用数组
 ```python
 class Solution:
     def isAnagram(self, s: str, t: str) -> bool:
@@ -153,59 +139,7 @@ class Solution:
         return True
 ```
 
-(版本三) 使用defaultdict
 
-```python
-from collections import defaultdict
-
-class Solution:
-    def isAnagram(self, s: str, t: str) -> bool:
-        
-        s_dict = defaultdict(int)
-        t_dict = defaultdict(int)
-
-        for x in s:
-            s_dict[x] += 1
-        
-        for x in t:
-            t_dict[x] += 1
-
-        return s_dict == t_dict
-```
-(版本四) 使用字典
-
-```python
-class Solution:
-    def isAnagram(self, s: str, t: str) -> bool:
-        if len(s) != len(t):
-            return False
-        
-        hash_table_s = {}
-        hash_table_t = {}
-        
-        for i in range(len(s)):
-            hash_table_s[s[i]] = hash_table_s.get(s[i], 0) + 1
-            hash_table_t[t[i]] = hash_table_t.get(t[i], 0) + 1
-            
-        return hash_table_s == hash_table_t
-```
-
-(版本五) 使用排序
-
-```python
-class Solution:
-    def isAnagram(self, s: str, t: str) -> bool:
-        return sorted(s) == sorted(t)
-```
-(版本六) 使用Counter
-
-```python
-from collections import Counter
-
-class Solution:
-    def isAnagram(self, s: str, t: str) -> bool:
-        return Counter(s) == Counter(t)
-```
 Go：
 
 ```go