diff --git a/problems/0027.移除元素.md b/problems/0027.移除元素.md
index 5e7742ee..762d3300 100644
--- a/problems/0027.移除元素.md
+++ b/problems/0027.移除元素.md
@@ -329,6 +329,22 @@ int removeElement(int* nums, int numsSize, int val){
}
```
+Scala:
+```scala
+object Solution {
+ def removeElement(nums: Array[Int], `val`: Int): Int = {
+ var slow = 0
+ for (fast <- 0 until nums.length) {
+ if (`val` != nums(fast)) {
+ nums(slow) = nums(fast)
+ slow += 1
+ }
+ }
+ slow
+ }
+}
+```
+
C#:
```csharp
public class Solution {
@@ -343,6 +359,5 @@ public class Solution {
}
}
```
-
-----------------------
diff --git a/problems/0035.搜索插入位置.md b/problems/0035.搜索插入位置.md
index 8a8f9706..6c04e7de 100644
--- a/problems/0035.搜索插入位置.md
+++ b/problems/0035.搜索插入位置.md
@@ -316,7 +316,26 @@ func searchInsert(_ nums: [Int], _ target: Int) -> Int {
return right + 1
}
```
-
+### Scala
+```scala
+object Solution {
+ def searchInsert(nums: Array[Int], target: Int): Int = {
+ var left = 0
+ var right = nums.length - 1
+ while (left <= right) {
+ var mid = left + (right - left) / 2
+ if (target == nums(mid)) {
+ return mid
+ } else if (target > nums(mid)) {
+ left = mid + 1
+ } else {
+ right = mid - 1
+ }
+ }
+ right + 1
+ }
+}
+```
### PHP
diff --git a/problems/0059.螺旋矩阵II.md b/problems/0059.螺旋矩阵II.md
index 4d5d80f6..22229302 100644
--- a/problems/0059.螺旋矩阵II.md
+++ b/problems/0059.螺旋矩阵II.md
@@ -130,57 +130,37 @@ Java：
```Java
class Solution {
public int[][] generateMatrix(int n) {
+ int loop = 0; // 控制循环次数
int[][] res = new int[n][n];
+ int start = 0; // 每次循环的开始点(start, start)
+ int count = 1; // 定义填充数字
+ int i, j;
- // 循环次数
- int loop = n / 2;
-
- // 定义每次循环起始位置
- int startX = 0;
- int startY = 0;
-
- // 定义偏移量
- int offset = 1;
-
- // 定义填充数字
- int count = 1;
-
- // 定义中间位置
- int mid = n / 2;
- while (loop > 0) {
- int i = startX;
- int j = startY;
-
+ while (loop++ < n / 2) { // 判断边界后，loop从1开始
// 模拟上侧从左到右
- for (; j startY; j--) {
+ for (; j >= loop; j--) {
res[i][j] = count++;
}
// 模拟左侧从下到上
- for (; i > startX; i--) {
+ for (; i >= loop; i--) {
res[i][j] = count++;
}
-
- loop--;
-
- startX += 1;
- startY += 1;
-
- offset += 2;
+ start++;
}
if (n % 2 == 1) {
- res[mid][mid] = count;
+ res[start][start] = count;
}
return res;
diff --git a/problems/0150.逆波兰表达式求值.md b/problems/0150.逆波兰表达式求值.md
index fd3d69aa..6ce7e2f9 100644
--- a/problems/0150.逆波兰表达式求值.md
+++ b/problems/0150.逆波兰表达式求值.md
@@ -136,19 +136,19 @@ java:
class Solution {
public int evalRPN(String[] tokens) {
Deque stack = new LinkedList();
- for (int i = 0; i < tokens.length; ++i) {
- if ("+".equals(tokens[i])) { // leetcode 内置jdk的问题，不能使用==判断字符串是否相等
+ for (String s : tokens) {
+ if ("+".equals(s)) { // leetcode 内置jdk的问题，不能使用==判断字符串是否相等
stack.push(stack.pop() + stack.pop()); // 注意 - 和/ 需要特殊处理
- } else if ("-".equals(tokens[i])) {
+ } else if ("-".equals(s)) {
stack.push(-stack.pop() + stack.pop());
- } else if ("*".equals(tokens[i])) {
+ } else if ("*".equals(s)) {
stack.push(stack.pop() * stack.pop());
- } else if ("/".equals(tokens[i])) {
+ } else if ("/".equals(s)) {
int temp1 = stack.pop();
int temp2 = stack.pop();
stack.push(temp2 / temp1);
} else {
- stack.push(Integer.valueOf(tokens[i]));
+ stack.push(Integer.valueOf(s));
}
}
return stack.pop();
diff --git a/problems/0188.买卖股票的最佳时机IV.md b/problems/0188.买卖股票的最佳时机IV.md
index 61c558a1..27eb38c3 100644
--- a/problems/0188.买卖股票的最佳时机IV.md
+++ b/problems/0188.买卖股票的最佳时机IV.md
@@ -409,5 +409,27 @@ var maxProfit = function(k, prices) {
};
```
+TypeScript：
+
+```typescript
+function maxProfit(k: number, prices: number[]): number {
+ const length: number = prices.length;
+ if (length === 0) return 0;
+ const dp: number[][] = new Array(length).fill(0)
+ .map(_ => new Array(k * 2 + 1).fill(0));
+ for (let i = 1; i <= k; i++) {
+ dp[0][i * 2 - 1] = -prices[0];
+ }
+ for (let i = 1; i < length; i++) {
+ for (let j = 1; j < 2 * k + 1; j++) {
+ dp[i][j] = Math.max(dp[i - 1][j], dp[i - 1][j - 1] + Math.pow(-1, j) * prices[i]);
+ }
+ }
+ return dp[length - 1][2 * k];
+};
+```
+
+
+
-----------------------
diff --git a/problems/0202.快乐数.md b/problems/0202.快乐数.md
index 51a79aff..be8686f7 100644
--- a/problems/0202.快乐数.md
+++ b/problems/0202.快乐数.md
@@ -386,6 +386,39 @@ bool isHappy(int n){
}
```
+Scala:
+```scala
+object Solution {
+ // 引入mutable
+ import scala.collection.mutable
+ def isHappy(n: Int): Boolean = {
+ // 存放每次计算后的结果
+ val set: mutable.HashSet[Int] = new mutable.HashSet[Int]()
+ var tmp = n // 因为形参是不可变量，所以需要找到一个临时变量
+ // 开始进入循环
+ while (true) {
+ val sum = getSum(tmp) // 获取这个数每个值的平方和
+ if (sum == 1) return true // 如果最终等于 1，则返回true
+ // 如果set里面已经有这个值了，说明进入无限循环，可以返回false，否则添加这个值到set
+ if (set.contains(sum)) return false
+ else set.add(sum)
+ tmp = sum
+ }
+ // 最终需要返回值，直接返回个false
+ false
+ }
+
+ def getSum(n: Int): Int = {
+ var sum = 0
+ var tmp = n
+ while (tmp != 0) {
+ sum += (tmp % 10) * (tmp % 10)
+ tmp = tmp / 10
+ }
+ sum
+ }
+
+
C#：
```csharp
public class Solution {
diff --git a/problems/0309.最佳买卖股票时机含冷冻期.md b/problems/0309.最佳买卖股票时机含冷冻期.md
index f3e7541b..f037fe85 100644
--- a/problems/0309.最佳买卖股票时机含冷冻期.md
+++ b/problems/0309.最佳买卖股票时机含冷冻期.md
@@ -325,6 +325,66 @@ const maxProfit = (prices) => {
};
```
+TypeScript：
+
+> 版本一，与本文思路一致
+
+```typescript
+function maxProfit(prices: number[]): number {
+ /**
+ dp[i][0]: 持股状态；
+ dp[i][1]: 无股状态，当天为非冷冻期；
+ dp[i][2]: 无股状态，当天卖出；
+ dp[i][3]: 无股状态，当天为冷冻期；
+ */
+ const length: number = prices.length;
+ const dp: number[][] = new Array(length).fill(0).map(_ => []);
+ dp[0][0] = -prices[0];
+ dp[0][1] = dp[0][2] = dp[0][3] = 0;
+ for (let i = 1; i < length; i++) {
+ dp[i][0] = Math.max(
+ dp[i - 1][0],
+ Math.max(dp[i - 1][1], dp[i - 1][3]) - prices[i]
+ );
+ dp[i][1] = Math.max(dp[i - 1][1], dp[i - 1][3]);
+ dp[i][2] = dp[i - 1][0] + prices[i];
+ dp[i][3] = dp[i - 1][2];
+ }
+ const lastEl: number[] = dp[length - 1];
+ return Math.max(lastEl[1], lastEl[2], lastEl[3]);
+};
+```
+
+> 版本二，状态定义略有不同，可以帮助理解
+
+```typescript
+function maxProfit(prices: number[]): number {
+ /**
+ dp[i][0]: 持股状态，当天买入；
+ dp[i][1]: 持股状态，当天未买入；
+ dp[i][2]: 无股状态，当天卖出；
+ dp[i][3]: 无股状态，当天未卖出；
+
+ 买入有冷冻期限制，其实就是状态[0]只能由前一天的状态[3]得到；
+ 如果卖出有冷冻期限制，其实就是[2]由[1]得到。
+ */
+ const length: number = prices.length;
+ const dp: number[][] = new Array(length).fill(0).map(_ => []);
+ dp[0][0] = -prices[0];
+ dp[0][1] = -Infinity;
+ dp[0][2] = dp[0][3] = 0;
+ for (let i = 1; i < length; i++) {
+ dp[i][0] = dp[i - 1][3] - prices[i];
+ dp[i][1] = Math.max(dp[i - 1][1], dp[i - 1][0]);
+ dp[i][2] = Math.max(dp[i - 1][0], dp[i - 1][1]) + prices[i];
+ dp[i][3] = Math.max(dp[i - 1][3], dp[i - 1][2]);
+ }
+ return Math.max(dp[length - 1][2], dp[length - 1][3]);
+};
+```
+
+
+
-----------------------
diff --git a/problems/0349.两个数组的交集.md b/problems/0349.两个数组的交集.md
index 7f8958d2..f7dab3d7 100644
--- a/problems/0349.两个数组的交集.md
+++ b/problems/0349.两个数组的交集.md
@@ -313,6 +313,50 @@ int* intersection1(int* nums1, int nums1Size, int* nums2, int nums2Size, int* re
}
```
+Scala:
+
+正常解法:
+```scala
+object Solution {
+ def intersection(nums1: Array[Int], nums2: Array[Int]): Array[Int] = {
+ // 导入mutable
+ import scala.collection.mutable
+ // 临时Set，用于记录数组1出现的每个元素
+ val tmpSet: mutable.HashSet[Int] = new mutable.HashSet[Int]()
+ // 结果Set，存储最终结果
+ val resSet: mutable.HashSet[Int] = new mutable.HashSet[Int]()
+ // 遍历nums1，把每个元素添加到tmpSet
+ nums1.foreach(tmpSet.add(_))
+ // 遍历nums2，如果在tmpSet存在就添加到resSet
+ nums2.foreach(elem => {
+ if (tmpSet.contains(elem)) {
+ resSet.add(elem)
+ }
+ })
+ // 将结果转换为Array返回，return可以省略
+ resSet.toArray
+ }
+}
+```
+骚操作1:
+```scala
+object Solution {
+ def intersection(nums1: Array[Int], nums2: Array[Int]): Array[Int] = {
+ // 先转为Set，然后取交集，最后转换为Array
+ (nums1.toSet).intersect(nums2.toSet).toArray
+ }
+}
+```
+骚操作2:
+```scala
+object Solution {
+ def intersection(nums1: Array[Int], nums2: Array[Int]): Array[Int] = {
+ // distinct去重，然后取交集
+ (nums1.distinct).intersect(nums2.distinct)
+ }
+}
+
+
C#:
```csharp
public int[] Intersection(int[] nums1, int[] nums2) {
@@ -330,6 +374,7 @@ C#:
}
return one;
}
+
```
## 相关题目
diff --git a/problems/0704.二分查找.md b/problems/0704.二分查找.md
index 55625130..1e474f9a 100644
--- a/problems/0704.二分查找.md
+++ b/problems/0704.二分查找.md
@@ -610,7 +610,48 @@ public class Solution{
}
}
```
+**Scala:**
+（版本一）左闭右闭区间
+```scala
+object Solution {
+ def search(nums: Array[Int], target: Int): Int = {
+ var left = 0
+ var right = nums.length - 1
+ while (left <= right) {
+ var mid = left + ((right - left) / 2)
+ if (target == nums(mid)) {
+ return mid
+ } else if (target < nums(mid)) {
+ right = mid - 1
+ } else {
+ left = mid + 1
+ }
+ }
+ -1
+ }
+}
+```
+（版本二）左闭右开区间
+```scala
+object Solution {
+ def search(nums: Array[Int], target: Int): Int = {
+ var left = 0
+ var right = nums.length
+ while (left < right) {
+ val mid = left + (right - left) / 2
+ if (target == nums(mid)) {
+ return mid
+ } else if (target < nums(mid)) {
+ right = mid
+ } else {
+ left = mid + 1
+ }
+ }
+ -1
+ }
+}
+```
-----------------------
diff --git a/problems/1002.查找常用字符.md b/problems/1002.查找常用字符.md
index 36937b0b..075b5ef1 100644
--- a/problems/1002.查找常用字符.md
+++ b/problems/1002.查找常用字符.md
@@ -418,6 +418,38 @@ char ** commonChars(char ** words, int wordsSize, int* returnSize){
return ret;
}
```
-
+Scala:
+```scala
+object Solution {
+ def commonChars(words: Array[String]): List[String] = {
+ // 声明返回结果的不可变List集合，因为res要重新赋值，所以声明为var
+ var res = List[String]()
+ var hash = new Array[Int](26) // 统计字符出现的最小频率
+ // 统计第一个字符串中字符出现的次数
+ for (i <- 0 until words(0).length) {
+ hash(words(0)(i) - 'a') += 1
+ }
+ // 统计其他字符串出现的频率
+ for (i <- 1 until words.length) {
+ // 统计其他字符出现的频率
+ var hashOtherStr = new Array[Int](26)
+ for (j <- 0 until words(i).length) {
+ hashOtherStr(words(i)(j) - 'a') += 1
+ }
+ // 更新hash，取26个字母最小出现的频率
+ for (k <- 0 until 26) {
+ hash(k) = math.min(hash(k), hashOtherStr(k))
+ }
+ }
+ // 根据hash的结果转换输出的形式
+ for (i <- 0 until 26) {
+ for (j <- 0 until hash(i)) {
+ res = res :+ (i + 'a').toChar.toString
+ }
+ }
+ res
+ }
+}
+```
-----------------------