添加(0474.一和零.md):增加typescript版本

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Steve2020
2022-05-05 14:15:00 +08:00
parent 28a8d2ea1c
commit 3c88974f92

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@ -323,6 +323,129 @@ const findMaxForm = (strs, m, n) => {
}; };
``` ```
TypeScript
> 滚动数组,二维数组法
```typescript
type BinaryInfo = { numOfZero: number, numOfOne: number };
function findMaxForm(strs: string[], m: number, n: number): number {
const goodsNum: number = strs.length;
const dp: number[][] = new Array(m + 1).fill(0)
.map(_ => new Array(n + 1).fill(0));
for (let i = 0; i < goodsNum; i++) {
const { numOfZero, numOfOne } = countBinary(strs[i]);
for (let j = m; j >= numOfZero; j--) {
for (let k = n; k >= numOfOne; k--) {
dp[j][k] = Math.max(dp[j][k], dp[j - numOfZero][k - numOfOne] + 1);
}
}
}
return dp[m][n];
};
function countBinary(str: string): BinaryInfo {
let numOfZero: number = 0,
numOfOne: number = 0;
for (let s of str) {
if (s === '0') {
numOfZero++;
} else {
numOfOne++;
}
}
return { numOfZero, numOfOne };
}
```
> 传统背包,三维数组法
```typescript
type BinaryInfo = { numOfZero: number, numOfOne: number };
function findMaxForm(strs: string[], m: number, n: number): number {
/**
dp[i][j][k]: 前i个物品中, 背包的0容量为j, 1容量为k, 最多能放的物品数量
*/
const goodsNum: number = strs.length;
const dp: number[][][] = new Array(goodsNum).fill(0)
.map(_ => new Array(m + 1)
.fill(0)
.map(_ => new Array(n + 1).fill(0))
);
const { numOfZero, numOfOne } = countBinary(strs[0]);
for (let i = numOfZero; i <= m; i++) {
for (let j = numOfOne; j <= n; j++) {
dp[0][i][j] = 1;
}
}
for (let i = 1; i < goodsNum; i++) {
const { numOfZero, numOfOne } = countBinary(strs[i]);
for (let j = 0; j <= m; j++) {
for (let k = 0; k <= n; k++) {
if (j < numOfZero || k < numOfOne) {
dp[i][j][k] = dp[i - 1][j][k];
} else {
dp[i][j][k] = Math.max(dp[i - 1][j][k], dp[i - 1][j - numOfZero][k - numOfOne] + 1);
}
}
}
}
return dp[dp.length - 1][m][n];
};
function countBinary(str: string): BinaryInfo {
let numOfZero: number = 0,
numOfOne: number = 0;
for (let s of str) {
if (s === '0') {
numOfZero++;
} else {
numOfOne++;
}
}
return { numOfZero, numOfOne };
}
```
> 回溯法(会超时)
```typescript
function findMaxForm(strs: string[], m: number, n: number): number {
/**
思路暴力枚举strs的所有子集记录符合条件子集的最大长度
*/
let resMax: number = 0;
backTrack(strs, m, n, 0, []);
return resMax;
function backTrack(
strs: string[], m: number, n: number,
startIndex: number, route: string[]
): void {
if (startIndex === strs.length) return;
for (let i = startIndex, length = strs.length; i < length; i++) {
route.push(strs[i]);
if (isValidSubSet(route, m, n)) {
resMax = Math.max(resMax, route.length);
backTrack(strs, m, n, i + 1, route);
}
route.pop();
}
}
};
function isValidSubSet(strs: string[], m: number, n: number): boolean {
let zeroNum: number = 0,
oneNum: number = 0;
strs.forEach(str => {
for (let s of str) {
if (s === '0') {
zeroNum++;
} else {
oneNum++;
}
}
});
return zeroNum <= m && oneNum <= n;
}
```
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