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Update 0530.二叉搜索树的最小绝对差.md - 增加了python3版本的迭代解法
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@ -222,6 +222,26 @@ class Solution:
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for i in range(len(res)-1): // 统计有序数组的最小差值
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r = min(abs(res[i]-res[i+1]),r)
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return r
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# 迭代法-中序遍历
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class Solution:
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def getMinimumDifference(self, root: TreeNode) -> int:
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stack = []
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cur = root
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pre = None
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result = float('inf')
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while cur or stack:
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if cur: # 指针来访问节点,访问到最底层
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stack.append(cur)
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cur = cur.left
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else: # 逐一处理节点
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cur = stack.pop()
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if pre: # 当前节点和前节点的值的差值
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result = min(result, cur.val - pre.val)
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pre = cur
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cur = cur.right
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return result
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```
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Go:
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> 中序遍历,然后计算最小差值
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