Update 0530.二叉搜索树的最小绝对差.md - 增加了python3版本的迭代解法

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藤露
2021-07-08 17:02:29 +08:00
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parent cd37799b72
commit 3ab914332e

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@ -222,6 +222,26 @@ class Solution:
for i in range(len(res)-1): // 统计有序数组的最小差值 for i in range(len(res)-1): // 统计有序数组的最小差值
r = min(abs(res[i]-res[i+1]),r) r = min(abs(res[i]-res[i+1]),r)
return r return r
# 迭代法-中序遍历
class Solution:
def getMinimumDifference(self, root: TreeNode) -> int:
stack = []
cur = root
pre = None
result = float('inf')
while cur or stack:
if cur: # 指针来访问节点,访问到最底层
stack.append(cur)
cur = cur.left
else: # 逐一处理节点
cur = stack.pop()
if pre: # 当前节点和前节点的值的差值
result = min(result, cur.val - pre.val)
pre = cur
cur = cur.right
return result
``` ```
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> 中序遍历,然后计算最小差值 > 中序遍历,然后计算最小差值