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更新 0236.二叉树的最近公共祖先 排版格式修复
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@ -34,12 +34,12 @@
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* 所有节点的值都是唯一的。
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* p、q 为不同节点且均存在于给定的二叉树中。
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# 算法公开课
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## 算法公开课
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**《代码随想录》算法视频公开课:[自底向上查找,有点难度! | LeetCode:236. 二叉树的最近公共祖先](https://www.bilibili.com/video/BV1jd4y1B7E2),相信结合视频在看本篇题解,更有助于大家对本题的理解**。
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**[《代码随想录》算法视频公开课](https://programmercarl.com/other/gongkaike.html):[自底向上查找,有点难度! | LeetCode:236. 二叉树的最近公共祖先](https://www.bilibili.com/video/BV1jd4y1B7E2),相信结合视频在看本篇题解,更有助于大家对本题的理解**。
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# 思路
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## 思路
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遇到这个题目首先想的是要是能自底向上查找就好了,这样就可以找到公共祖先了。
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@ -226,7 +226,7 @@ public:
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};
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```
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# 总结
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## 总结
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这道题目刷过的同学未必真正了解这里面回溯的过程,以及结果是如何一层一层传上去的。
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@ -243,10 +243,10 @@ public:
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本题没有给出迭代法,因为迭代法不适合模拟回溯的过程。理解递归的解法就够了。
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# 其他语言版本
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## 其他语言版本
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## Java
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### Java
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```Java
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class Solution {
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@ -273,7 +273,7 @@ class Solution {
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```
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## Python
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### Python
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递归法(版本一)
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```python
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class Solution:
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@ -312,7 +312,7 @@ class Solution:
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return left
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```
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## Go
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### Go
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```Go
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func lowestCommonAncestor(root, p, q *TreeNode) *TreeNode {
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@ -343,7 +343,7 @@ func lowestCommonAncestor(root, p, q *TreeNode) *TreeNode {
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}
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```
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## JavaScript
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### JavaScript
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```javascript
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var lowestCommonAncestor = function(root, p, q) {
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@ -370,7 +370,7 @@ var lowestCommonAncestor = function(root, p, q) {
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};
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```
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## TypeScript
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### TypeScript
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```typescript
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function lowestCommonAncestor(root: TreeNode | null, p: TreeNode | null, q: TreeNode | null): TreeNode | null {
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@ -384,7 +384,7 @@ function lowestCommonAncestor(root: TreeNode | null, p: TreeNode | null, q: Tree
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};
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```
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## Scala
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### Scala
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```scala
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object Solution {
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@ -404,7 +404,7 @@ object Solution {
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}
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```
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## rust
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### Rust
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```rust
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impl Solution {
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@ -436,3 +436,4 @@ impl Solution {
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<img src="../pics/网站星球宣传海报.jpg" width="1000"/>
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</a>
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