From 352b51d550a6edcc9b6355b8773b91d4f69cb507 Mon Sep 17 00:00:00 2001
From: jianghongcheng <35664721+jianghongcheng@users.noreply.github.com>
Date: Thu, 1 Jun 2023 02:36:11 -0500
Subject: [PATCH] =?UTF-8?q?Update=200056.=E5=90=88=E5=B9=B6=E5=8C=BA?=
 =?UTF-8?q?=E9=97=B4.md?=
MIME-Version: 1.0
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---
 problems/0056.合并区间.md | 22 ++++++++++++++--------
 1 file changed, 14 insertions(+), 8 deletions(-)

diff --git a/problems/0056.合并区间.md b/problems/0056.合并区间.md
index 952d32af..ead2fb75 100644
--- a/problems/0056.合并区间.md
+++ b/problems/0056.合并区间.md
@@ -141,18 +141,24 @@ class Solution {
 ### Python 
 ```python
 class Solution:
-    def merge(self, intervals: List[List[int]]) -> List[List[int]]:
-        if len(intervals) == 0: return intervals
-        intervals.sort(key=lambda x: x[0])
+    def merge(self, intervals):
         result = []
-        result.append(intervals[0])
+        if len(intervals) == 0:
+            return result  # 区间集合为空直接返回
+
+        intervals.sort(key=lambda x: x[0])  # 按照区间的左边界进行排序
+
+        result.append(intervals[0])  # 第一个区间可以直接放入结果集中
+
         for i in range(1, len(intervals)):
-            last = result[-1]
-            if last[1] >= intervals[i][0]:
-                result[-1] = [last[0], max(last[1], intervals[i][1])]
+            if result[-1][1] >= intervals[i][0]:  # 发现重叠区间
+                # 合并区间，只需要更新结果集最后一个区间的右边界，因为根据排序，左边界已经是最小的
+                result[-1][1] = max(result[-1][1], intervals[i][1])
             else:
-                result.append(intervals[i])
+                result.append(intervals[i])  # 区间不重叠
+
         return result
+
 ```
 
 ### Go