From 34f4a7b7ba3c240db160d710df054c0f8b7732ab Mon Sep 17 00:00:00 2001
From: yqq <youngqqcn@163.com>
Date: Sun, 19 Sep 2021 18:13:54 +0800
Subject: [PATCH] =?UTF-8?q?925.=E9=95=BF=E6=8C=89=E9=94=AE=E5=85=A5=20,=20?=
 =?UTF-8?q?=E5=A2=9E=E5=8A=A0Golang=E5=AE=9E=E7=8E=B0?=
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---
 problems/0925.长按键入.md | 26 +++++++++++++++++++++++++-
 1 file changed, 25 insertions(+), 1 deletion(-)

diff --git a/problems/0925.长按键入.md b/problems/0925.长按键入.md
index 3502f2fb..70597508 100644
--- a/problems/0925.长按键入.md
+++ b/problems/0925.长按键入.md
@@ -134,7 +134,7 @@ Python：
 class Solution:
     def isLongPressedName(self, name: str, typed: str) -> bool:
         i, j = 0, 0
-        m, n = len(name) , len(typed) 
+        m, n = len(name) , len(typed)
         while i< m and j < n:
             if name[i] == typed[j]: # 相同时向后匹配
                 i += 1
@@ -155,8 +155,32 @@ class Solution:
             else: return False
         return True
 ```
+
 Go：
 
+```go
+
+func isLongPressedName(name string, typed string) bool {
+	if(name[0] != typed[0] || len(name) > len(typed)) {
+		return false;
+	}
+
+	idx := 0 // name的索引
+	var last byte  // 上个匹配字符
+	for i := 0; i < len(typed); i++ {
+		if idx < len(name) && name[idx] == typed[i] {
+			last = name[idx]
+			idx++
+		} else if last == typed[i] {
+			continue
+		} else  {
+			return false
+		}
+	}
+	return idx == len(name)
+}
+```
+
 JavaScript：
 
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