mirror of
https://github.com/youngyangyang04/leetcode-master.git
synced 2025-07-09 19:44:45 +08:00
@ -493,6 +493,9 @@ function threeSum(nums: number[]): number[][] {
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right: number = length - 1;
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let resArr: number[][] = [];
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for (let i = 0; i < length; i++) {
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if (nums[i]>0) {
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return resArr; //nums经过排序后,只要nums[i]>0, 此后的nums[i] + nums[left] + nums[right]均大于0,可以提前终止循环。
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}
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if (i > 0 && nums[i] === nums[i - 1]) {
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continue;
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}
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@ -191,18 +191,20 @@ TypeScript:
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```typescript
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function removeNthFromEnd(head: ListNode | null, n: number): ListNode | null {
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let newHead: ListNode | null = new ListNode(0, head);
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let slowNode: ListNode | null = newHead,
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fastNode: ListNode | null = newHead;
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for (let i = 0; i < n; i++) {
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fastNode = fastNode.next;
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//根据leetcode题目的定义可推断这里快慢指针均不需要定义为ListNode | null。
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let slowNode: ListNode = newHead;
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let fastNode: ListNode = newHead;
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while(n--) {
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fastNode = fastNode.next!; //由虚拟头节点前进n个节点时,fastNode.next可推断不为null。
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}
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while (fastNode.next) {
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while(fastNode.next) { //遍历直至fastNode.next = null, 即尾部节点。 此时slowNode指向倒数第n个节点。
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fastNode = fastNode.next;
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slowNode = slowNode.next;
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slowNode = slowNode.next!;
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}
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slowNode.next = slowNode.next.next;
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slowNode.next = slowNode.next!.next; //倒数第n个节点可推断其next节点不为空。
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return newHead.next;
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};
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}
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```
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版本二(计算节点总数法):
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@ -385,7 +385,8 @@ function removeElements(head: ListNode | null, val: number): ListNode | null {
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if (cur.val === val) {
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pre.next = cur.next;
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} else {
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pre = pre.next;
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//此处不加类型断言时:编译器会认为pre类型为ListNode, pre.next类型为ListNode | null
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pre = pre.next as ListNode;
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}
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cur = cur.next;
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}
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@ -186,7 +186,7 @@ TypeScript:
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```typescript
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class ListNode {
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public val: number;
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public next: ListNode = null;
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public next: ListNode|null = null;
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constructor(value: number) {
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this.val = value;
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this.next = null;
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