From 2c52c3c363e13803ff9b46c16e9ec37ead8fe41c Mon Sep 17 00:00:00 2001
From: Leehouc <152672308+Leehouc@users.noreply.github.com>
Date: Fri, 30 Aug 2024 21:31:45 +0800
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---
 problems/kamacoder/0058.区间和.md | 42 ++++++++++++++++++++++++++++
 1 file changed, 42 insertions(+)

diff --git a/problems/kamacoder/0058.区间和.md b/problems/kamacoder/0058.区间和.md
index f5ce08dc..c5a84a29 100644
--- a/problems/kamacoder/0058.区间和.md
+++ b/problems/kamacoder/0058.区间和.md
@@ -263,3 +263,45 @@ if __name__ == "__main__":
     main()
 
 ```
+### C
+
+```C
+#include <stdio.h>
+#include <stdlib.h>
+
+int main(int argc, char *argv[])
+{
+    int num;
+    // 读取数组长度
+    scanf("%d", &num);
+
+    // 使用动态内存分配而不是静态数组，以适应不同的输入大小
+    int *a = (int *)malloc((num + 1) * sizeof(int));
+
+    // 初始化前缀和数组的第一个元素为0
+    a[0] = 0;
+
+    // 读取数组元素并计算前缀和
+    for (int i = 1; i <= num; i++)
+    {
+        int mm;
+        scanf("%d", &mm);
+        // 累加前缀和
+        a[i] = a[i - 1] + mm;
+    }
+
+    int m, n;
+    // 循环读取区间并计算区间和，直到输入结束
+    // scanf()返回成功匹配和赋值的个数,到达文件末尾则返回 EOF
+    while (scanf("%d%d", &m, &n) == 2)
+    {
+        // 输出区间和，注意区间是左闭右开，因此a[n+1]是包含n的元素的前缀和
+        printf("%d\n", a[n+1] - a[m]);
+    }
+
+    // 释放之前分配的内存
+    free(a);
+    return 0;
+}
+
+```