From 2c1d0927d2e7f88b256451bdca5f6ef04be81de6 Mon Sep 17 00:00:00 2001
From: Powerstot <77142630+Powerstot@users.noreply.github.com>
Date: Wed, 12 May 2021 20:55:21 +0800
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添加0541.反转字符串II Java版本
---
 problems/0541.反转字符串II.md | 29 +++++++++++++++++++++++++++++
 1 file changed, 29 insertions(+)

diff --git a/problems/0541.反转字符串II.md b/problems/0541.反转字符串II.md
index 6a84006e..7ca63675 100644
--- a/problems/0541.反转字符串II.md
+++ b/problems/0541.反转字符串II.md
@@ -101,7 +101,36 @@ public:
 
 
 Java：
+```Java
+class Solution {
+    public String reverseStr(String s, int k) {
+        StringBuffer res = new StringBuffer();
 
+        for (int i = 0; i < s.length(); i += (2 * k)) {
+            StringBuffer temp = new StringBuffer();
+            // 剩余字符大于 k 个，每隔 2k 个字符的前 k 个字符进行反转
+            if (i + k <= s.length()) {
+                // 反转前 k 个字符
+                temp.append(s.substring(i, i + k));
+                res.append(temp.reverse());
+
+                // 反转完前 k 个字符之后，如果紧接着还有 k 个字符，则直接加入这 k 个字符
+                if (i + 2 * k <= s.length()) {
+                    res.append(s.substring(i + k, i + 2 * k));
+                // 不足 k 个字符，则直接加入剩下所有字符
+                } else {
+                    res.append(s.substring(i + k, s.length()));
+                }
+                continue;
+            }
+            // 剩余字符少于 k 个，则将剩余字符全部反转。
+            temp.append(s.substring(i, s.length()));
+            res.append(temp.reverse());
+        }
+        return res.toString();
+    }
+}
+```
 
 Python：