diff --git a/problems/0491.递增子序列.md b/problems/0491.递增子序列.md index ea113f4b..9f61ae45 100644 --- a/problems/0491.递增子序列.md +++ b/problems/0491.递增子序列.md @@ -313,7 +313,72 @@ var findSubsequences = function(nums) { ``` +C: +```c +int* path; +int pathTop; +int** ans; +int ansTop; +int* length; +//将当前path中的内容复制到ans中 +void copy() { + int* tempPath = (int*)malloc(sizeof(int) * pathTop); + memcpy(tempPath, path, pathTop * sizeof(int)); + length[ansTop] = pathTop; + ans[ansTop++] = tempPath; +} +//查找uset中是否存在值为key的元素 +int find(int* uset, int usetSize, int key) { + int i; + for(i = 0; i < usetSize; i++) { + if(uset[i] == key) + return 1; + } + return 0; +} + +void backTracking(int* nums, int numsSize, int startIndex) { + //当path中元素大于1个时,将path拷贝到ans中 + if(pathTop > 1) { + copy(); + } + int* uset = (int*)malloc(sizeof(int) * numsSize); + int usetTop = 0; + int i; + for(i = startIndex; i < numsSize; i++) { + //若当前元素小于path中最后一位元素 || 在树的同一层找到了相同的元素,则continue + if((pathTop > 0 && nums[i] < path[pathTop - 1]) || find(uset, usetTop, nums[i])) + continue; + //将当前元素放入uset + uset[usetTop++] = nums[i]; + //将当前元素放入path + path[pathTop++] = nums[i]; + backTracking(nums, numsSize, i + 1); + //回溯 + pathTop--; + } +} + +int** findSubsequences(int* nums, int numsSize, int* returnSize, int** returnColumnSizes){ + //辅助数组初始化 + path = (int*)malloc(sizeof(int) * numsSize); + ans = (int**)malloc(sizeof(int*) * 33000); + length = (int*)malloc(sizeof(int*) * 33000); + pathTop = ansTop = 0; + + backTracking(nums, numsSize, 0); + + //设置数组中返回元素个数,以及每个一维数组的长度 + *returnSize = ansTop; + *returnColumnSizes = (int*)malloc(sizeof(int) * ansTop); + int i; + for(i = 0; i < ansTop; i++) { + (*returnColumnSizes)[i] = length[i]; + } + return ans; +} +``` -----------------------