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更新0704.二分查找,java版本
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@ -153,6 +153,10 @@ Java:
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```java
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class Solution {
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public int search(int[] nums, int target) {
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// 避免当 target 小于nums[0] nums[nums.length - 1]时多次循环运算
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if (target < nums[0] || target > nums[nums.length - 1]) {
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return -1;
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}
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int left = 0, right = nums.length - 1;
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while (left <= right) {
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int mid = left + ((right - left) >> 1);
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