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Merge pull request #1745 from EnzoSeason/leetcode-101
Update 0101.对称二叉树.md
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@ -754,23 +754,77 @@ func isSymmetric3(_ root: TreeNode?) -> Bool {
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## Scala
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## Scala
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递归:
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> 递归:
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```scala
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```scala
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object Solution {
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object Solution {
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def isSymmetric(root: TreeNode): Boolean = {
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def isSymmetric(root: TreeNode): Boolean = {
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if (root == null) return true // 如果等于空直接返回true
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if (root == null) return true // 如果等于空直接返回true
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def compare(left: TreeNode, right: TreeNode): Boolean = {
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def compare(left: TreeNode, right: TreeNode): Boolean = {
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if (left == null && right == null) return true // 如果左右都为空,则为true
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if (left == null && right == null) true // 如果左右都为空,则为true
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if (left == null && right != null) return false // 如果左空右不空,不对称,返回false
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else if (left == null && right != null) false // 如果左空右不空,不对称,返回false
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if (left != null && right == null) return false // 如果左不空右空,不对称,返回false
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else if (left != null && right == null) false // 如果左不空右空,不对称,返回false
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// 如果左右的值相等,并且往下递归
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// 如果左右的值相等,并且往下递归
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left.value == right.value && compare(left.left, right.right) && compare(left.right, right.left)
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else left.value == right.value && compare(left.left, right.right) && compare(left.right, right.left)
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}
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}
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// 分别比较左子树和右子树
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// 分别比较左子树和右子树
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compare(root.left, root.right)
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compare(root.left, root.right)
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}
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}
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}
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}
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```
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```
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> 迭代 - 使用栈
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```scala
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object Solution {
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import scala.collection.mutable
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def isSymmetric(root: TreeNode): Boolean = {
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if (root == null) return true
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val cache = mutable.Stack[(TreeNode, TreeNode)]((root.left, root.right))
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while (cache.nonEmpty) {
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cache.pop() match {
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case (null, null) =>
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case (_, null) => return false
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case (null, _) => return false
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case (left, right) =>
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if (left.value != right.value) return false
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cache.push((left.left, right.right))
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cache.push((left.right, right.left))
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}
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}
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true
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}
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}
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```
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> 迭代 - 使用队列
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```scala
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object Solution {
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import scala.collection.mutable
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def isSymmetric(root: TreeNode): Boolean = {
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if (root == null) return true
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val cache = mutable.Queue[(TreeNode, TreeNode)]((root.left, root.right))
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while (cache.nonEmpty) {
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cache.dequeue() match {
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case (null, null) =>
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case (_, null) => return false
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case (null, _) => return false
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case (left, right) =>
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if (left.value != right.value) return false
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cache.enqueue((left.left, right.right))
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cache.enqueue((left.right, right.left))
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}
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}
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true
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}
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}
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```
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<p align="center">
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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