Merge pull request #305 from flames519/master

101，104， 111 go版本

problems/0101.对称二叉树.md

@@ -363,6 +363,54 @@ Python：
 
 Go：
 
+```go
+/**
+ * Definition for a binary tree node.
+ * type TreeNode struct {
+ *     Val int
+ *     Left *TreeNode
+ *     Right *TreeNode
+ * }
+ */
+// 递归
+func defs(left *TreeNode, right *TreeNode) bool {
+    if left == nil && right == nil {
+        return true;
+    };
+    if left == nil || right == nil {
+        return false;
+    };
+    if left.Val != right.Val {
+        return false;
+    }
+    return defs(left.Left, right.Right) && defs(right.Left, left.Right);
+}
+func isSymmetric(root *TreeNode) bool {
+    return defs(root.Left, root.Right);
+}
+
+// 迭代
+func isSymmetric(root *TreeNode) bool {
+    var queue []*TreeNode;
+    if root != nil {
+        queue = append(queue, root.Left, root.Right);
+    }
+    for len(queue) > 0 {
+        left := queue[0];
+        right := queue[1];
+        queue = queue[2:];
+        if left == nil && right == nil {
+            continue;
+        }
+        if left == nil || right == nil || left.Val != right.Val {
+            return false;
+        };
+        queue = append(queue, left.Left, right.Right, right.Left, left.Right);
+    }
+    return true;
+}
+```
+
 
 JavaScript
 ```javascript

problems/0104.二叉树的最大深度.md

@@ -284,6 +284,55 @@ Python：
 
 Go：
 
+```go
+/**
+ * Definition for a binary tree node.
+ * type TreeNode struct {
+ *     Val int
+ *     Left *TreeNode
+ *     Right *TreeNode
+ * }
+ */
+func max (a, b int) int {
+    if a > b {
+        return a;
+    }
+    return b;
+}
+// 递归
+func maxDepth(root *TreeNode) int {
+    if root == nil {
+        return 0;
+    }
+    return max(maxDepth(root.Left), maxDepth(root.Right)) + 1;
+}
+
+// 遍历
+func maxDepth(root *TreeNode) int {
+    levl := 0;
+    queue := make([]*TreeNode, 0);
+    if root != nil {
+        queue = append(queue, root);
+    }
+    for l := len(queue); l > 0; {
+        for ;l > 0;l-- {
+            node := queue[0];
+            if node.Left != nil {
+                queue = append(queue, node.Left);
+            }
+            if node.Right != nil {
+                queue = append(queue, node.Right);
+            }
+            queue = queue[1:];
+        }
+        levl++;
+        l = len(queue);
+    }
+    return levl;
+}
+
+```
+
 
 JavaScript
 ```javascript

problems/0111.二叉树的最小深度.md

@@ -301,6 +301,64 @@ class Solution:
 
 Go：
 
+```go
+/**
+ * Definition for a binary tree node.
+ * type TreeNode struct {
+ *     Val int
+ *     Left *TreeNode
+ *     Right *TreeNode
+ * }
+ */
+func min(a, b int) int {
+    if a < b {
+        return a;
+    }
+    return b;
+}
+// 递归
+func minDepth(root *TreeNode) int {
+    if root == nil {
+        return 0;
+    }
+    if root.Left == nil && root.Right != nil {
+        return 1 + minDepth(root.Right);
+    }
+    if root.Right == nil && root.Left != nil {
+        return 1 + minDepth(root.Left);
+    }
+    return min(minDepth(root.Left), minDepth(root.Right)) + 1;
+}
+
+// 迭代
+
+func minDepth(root *TreeNode) int {
+    dep := 0;
+    queue := make([]*TreeNode, 0);
+    if root != nil {
+        queue = append(queue, root);
+    }
+    for l := len(queue); l > 0; {
+        dep++;
+        for ; l > 0; l-- {
+            node := queue[0];
+            if node.Left == nil && node.Right == nil {
+                return dep;
+            }
+            if node.Left != nil {
+                queue = append(queue, node.Left);
+            }
+            if node.Right != nil {
+                queue = append(queue, node.Right);
+            }
+            queue = queue[1:];
+        }
+        l = len(queue);
+    } 
+    return dep;
+}
+```
+
 
 JavaScript: