From 19b76720a2277f7ca8a72ffdf7e1a7c810bfe951 Mon Sep 17 00:00:00 2001
From: Vox Dai <vox.dai@icloud.com>
Date: Sun, 21 Apr 2024 09:37:42 +0800
Subject: [PATCH] =?UTF-8?q?Update=20'''0222.=E5=AE=8C=E5=85=A8=E4=BA=8C?=
 =?UTF-8?q?=E5=8F=89=E6=A0=91=E7=9A=84=E8=8A=82=E7=82=B9=E4=B8=AA=E6=95=B0?=
 =?UTF-8?q?.md'''=20Fix=20Typo?=
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修复部分代码块无高亮
---
 problems/0222.完全二叉树的节点个数.md | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

diff --git a/problems/0222.完全二叉树的节点个数.md b/problems/0222.完全二叉树的节点个数.md
index d93d2a33..69403607 100644
--- a/problems/0222.完全二叉树的节点个数.md
+++ b/problems/0222.完全二叉树的节点个数.md
@@ -54,7 +54,7 @@
 1. 确定递归函数的参数和返回值：参数就是传入树的根节点，返回就返回以该节点为根节点二叉树的节点数量，所以返回值为int类型。
 
 代码如下：
-```
+```CPP
 int getNodesNum(TreeNode* cur) {
 ```
 
@@ -62,7 +62,7 @@ int getNodesNum(TreeNode* cur) {
 
 代码如下：
 
-```
+```CPP
 if (cur == NULL) return 0;
 ```
 
@@ -70,7 +70,7 @@ if (cur == NULL) return 0;
 
 代码如下：
 
-```
+```CPP
 int leftNum = getNodesNum(cur->left);      // 左
 int rightNum = getNodesNum(cur->right);    // 右
 int treeNum = leftNum + rightNum + 1;      // 中