From 66c3aab86a1c979ca14244c65ee2564be6e288d4 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E7=8F=82=E7=8F=82?= <keboom518@163.com>
Date: Tue, 1 Mar 2022 11:27:42 +0800
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---
 problems/0738.单调递增的数字.md | 24 ++++++++++--------------
 1 file changed, 10 insertions(+), 14 deletions(-)

diff --git a/problems/0738.单调递增的数字.md b/problems/0738.单调递增的数字.md
index e670bb31..c8ce8a2b 100644
--- a/problems/0738.单调递增的数字.md
+++ b/problems/0738.单调递增的数字.md
@@ -148,23 +148,19 @@ java版本1中创建了String数组，多次使用Integer.parseInt了方法，
 版本2
 class Solution {
     public int monotoneIncreasingDigits(int n) {
-        if (n==0)return 0;
-        char[] chars= Integer.toString(n).toCharArray();
-        int start=Integer.MAX_VALUE;//start初始值设为最大值，这是为了防止当数字本身是单调递增时，没有一位数字需要改成9的情况
-        for (int i=chars.length-1;i>0;i--){
-            if (chars[i]<chars[i-1]){
-                chars[i-1]--;
-                start=i;
+        String s = String.valueOf(n);
+        char[] chars = s.toCharArray();
+        int start = s.length();
+        for (int i = s.length() - 2; i >= 0; i--) {
+            if (chars[i] > chars[i + 1]) {
+                chars[i]--;
+                start = i+1;
             }
         }
-        StringBuilder res=new StringBuilder();
-        for (int i=0;i<chars.length;i++){
-            if (chars[i]=='0'&&i==0)continue;//防止出现09这样的情况
-            if (i>=start){
-                res.append('9');
-            }else res.append(chars[i]);
+        for (int i = start; i < s.length(); i++) {
+            chars[i] = '9';
         }
-        return Integer.parseInt(res.toString());
+        return Integer.parseInt(String.valueOf(chars));
     }
 }
 ```