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update 0063.不同路径II.md Go版本
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@ -272,40 +272,27 @@ func uniquePathsWithObstacles(obstacleGrid [][]int) int {
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for i, _ := range dp {
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for i, _ := range dp {
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dp[i] = make([]int, n)
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dp[i] = make([]int, n)
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}
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}
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// 初始化
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// 初始化, 如果是障碍物, 后面的就都是0, 不用循环了
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for i:=0;i<m;i++ {
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for i := 0; i < m && obstacleGrid[i][0] == 0; i++ {
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// 如果是障碍物, 后面的就都是0, 不用循环了
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if obstacleGrid[i][0] == 1 {
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break
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}
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dp[i][0] = 1
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dp[i][0] = 1
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}
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}
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for i:=0;i<n;i++ {
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for i := 0; i < n && obstacleGrid[0][i] == 0; i++ {
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if obstacleGrid[0][i] == 1 {
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break
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}
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dp[0][i] = 1
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dp[0][i] = 1
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}
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}
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// dp数组推导过程
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// dp数组推导过程
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for i := 1; i < m; i++ {
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for i := 1; i < m; i++ {
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for j := 1; j < n; j++ {
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for j := 1; j < n; j++ {
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// 如果obstacleGrid[i][j]这个点是障碍物, 那么我们的dp[i][j]保持为0
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// 如果obstacleGrid[i][j]这个点是障碍物, 那么dp[i][j]保持为0
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if obstacleGrid[i][j] != 1 {
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if obstacleGrid[i][j] != 1 {
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// 否则我们需要计算当前点可以到达的路径数
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// 否则我们需要计算当前点可以到达的路径数
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dp[i][j] = dp[i-1][j] + dp[i][j-1]
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dp[i][j] = dp[i-1][j] + dp[i][j-1]
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}
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}
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}
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}
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}
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}
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// debug遍历dp
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//for i,_ := range dp {
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// for j,_ := range dp[i] {
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// fmt.Printf("%.2v,",dp[i][j])
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// }
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// fmt.Println()
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//}
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return dp[m-1][n-1]
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return dp[m-1][n-1]
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}
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}
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```
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```
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Javascript
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Javascript
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