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优化二叉树层序遍历116和117题的go方法
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@ -1891,13 +1891,12 @@ go:
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*/
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func connect(root *Node) *Node {
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res:=[][]*Node{}
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if root == nil { //防止为空
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return root
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}
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queue := list.New()
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queue.PushBack(root)
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var tmpArr []*Node
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tmpArr := make([]*Node, 0)
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for queue.Len() > 0 {
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length := queue.Len() //保存当前层的长度,然后处理当前层(十分重要,防止添加下层元素影响判断层中元素的个数)
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for i := 0; i < length; i++ {
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@ -1910,17 +1909,17 @@ func connect(root *Node) *Node {
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}
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tmpArr = append(tmpArr, node) //将值加入本层切片中
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}
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res=append(res,tmpArr)//放入结果集
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tmpArr=[]*Node{}//清空层的数据
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}
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if len(tmpArr) > 1 {
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// 遍历每层元素,指定next
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for i:=0;i<len(res);i++{
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for j:=0;j<len(res[i])-1;j++{
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res[i][j].Next=res[i][j+1]
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for i := 0; i < len(tmpArr)-1; i++ {
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tmpArr[i].Next = tmpArr[i+1]
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}
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}
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tmpArr = []*Node{} //清空层的数据
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}
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return root
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}
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```
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Swift:
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@ -2172,13 +2171,12 @@ go:
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*/
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func connect(root *Node) *Node {
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res:=[][]*Node{}
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if root == nil { //防止为空
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return root
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}
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queue := list.New()
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queue.PushBack(root)
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var tmpArr []*Node
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tmpArr := make([]*Node, 0)
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for queue.Len() > 0 {
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length := queue.Len() //保存当前层的长度,然后处理当前层(十分重要,防止添加下层元素影响判断层中元素的个数)
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for i := 0; i < length; i++ {
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@ -2191,15 +2189,14 @@ func connect(root *Node) *Node {
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}
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tmpArr = append(tmpArr, node) //将值加入本层切片中
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}
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res=append(res,tmpArr)//放入结果集
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tmpArr=[]*Node{}//清空层的数据
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}
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if len(tmpArr) > 1 {
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// 遍历每层元素,指定next
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for i:=0;i<len(res);i++{
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for j:=0;j<len(res[i])-1;j++{
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res[i][j].Next=res[i][j+1]
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for i := 0; i < len(tmpArr)-1; i++ {
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tmpArr[i].Next = tmpArr[i+1]
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}
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}
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tmpArr = []*Node{} //清空层的数据
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}
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return root
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}
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```
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