diff --git a/problems/0053.最大子序和（动态规划）.md b/problems/0053.最大子序和（动态规划）.md
index 1efd7e12..4c2a2944 100644
--- a/problems/0053.最大子序和（动态规划）.md
+++ b/problems/0053.最大子序和（动态规划）.md
@@ -173,7 +173,8 @@ JavaScript：
 ```javascript
 const maxSubArray = nums => {
     // 数组长度，dp初始化
-    const [len, dp] = [nums.length, [nums[0]]];
+    const len = nums.length;
+    let dp = new Array(len).fill(0);
     // 最大值初始化为dp[0]
     let max = dp[0];
     for (let i = 1; i < len; i++) {
diff --git a/problems/0090.子集II.md b/problems/0090.子集II.md
index 5ab881e7..e970d752 100644
--- a/problems/0090.子集II.md
+++ b/problems/0090.子集II.md
@@ -279,6 +279,74 @@ var subsetsWithDup = function(nums) {
 
 ```
 
+C:
+```c
+int* path;
+int pathTop;
+int** ans;
+int ansTop;
+//负责存放二维数组中每个数组的长度
+int* lengths;
+//快排cmp函数
+int cmp(const void* a, const void* b) {
+    return *((int*)a) - *((int*)b);
+}
+
+//复制函数，将当前path中的元素复制到ans中。同时记录path长度
+void copy() {
+    int* tempPath = (int*)malloc(sizeof(int) * pathTop);
+    int i;
+    for(i = 0; i < pathTop; i++) {
+        tempPath[i] = path[i];
+    }
+    ans = (int**)realloc(ans, sizeof(int*) * (ansTop + 1));
+    lengths[ansTop] = pathTop;
+    ans[ansTop++] = tempPath;
+}
+
+void backTracking(int* nums, int numsSize, int startIndex, int* used) {
+    //首先将当前path复制
+    copy();
+    //若startIndex大于数组最后一位元素的位置，返回
+    if(startIndex >= numsSize)
+        return ;
+    
+    int i;
+    for(i = startIndex; i < numsSize; i++) {
+        //对同一树层使用过的元素进行跳过
+        if(i > 0 && nums[i] ==  nums[i-1] && used[i-1] == false) 
+            continue;
+        path[pathTop++] = nums[i];
+        used[i] = true;
+        backTracking(nums, numsSize, i + 1, used);
+        used[i] = false;
+        pathTop--;
+    }
+}
+
+int** subsetsWithDup(int* nums, int numsSize, int* returnSize, int** returnColumnSizes){
+    //声明辅助变量
+    path = (int*)malloc(sizeof(int) * numsSize);
+    ans = (int**)malloc(0);
+    lengths = (int*)malloc(sizeof(int) * 1500);
+    int* used = (int*)malloc(sizeof(int) * numsSize);
+    pathTop = ansTop = 0;
+
+    //排序后查重才能生效
+    qsort(nums, numsSize, sizeof(int), cmp);
+    backTracking(nums, numsSize, 0, used);
+
+    //设置一维数组和二维数组的返回大小
+    *returnSize = ansTop;
+    *returnColumnSizes = (int*)malloc(sizeof(int) * ansTop);
+    int i;
+    for(i = 0; i < ansTop; i++) {
+        (*returnColumnSizes)[i] = lengths[i];
+    }
+    return ans;
+}
+```
+
 
 
 -----------------------
diff --git a/problems/0406.根据身高重建队列.md b/problems/0406.根据身高重建队列.md
index bd27b1b2..3c6ee63c 100644
--- a/problems/0406.根据身高重建队列.md
+++ b/problems/0406.根据身高重建队列.md
@@ -222,7 +222,7 @@ class Solution:
 ```
 
 Go：
-```golang
+```go
 func reconstructQueue(people [][]int) [][]int {
     //先将身高从大到小排序，确定最大个子的相对位置
     sort.Slice(people,func(i,j int)bool{
@@ -241,7 +241,38 @@ func reconstructQueue(people [][]int) [][]int {
 	return result
 }
 ```
+```go
+//链表法
+func reconstructQueue(people [][]int) [][]int {
+     sort.Slice(people,func (i,j int) bool {
+        if people[i][0]==people[j][0]{
+            return people[i][1]<people[j][1]//当身高相同时，将K按照从小到大排序
+        }
+         //先将身高从大到小排序，确定最大个子的相对位置
+        return people[i][0]>people[j][0]
+    })
+    l:=list.New()//创建链表
+    for i:=0;i<len(people);i++{
+        position:=people[i][1]
+        mark:=l.PushBack(people[i])//插入元素
+        e:=l.Front()
+        for position!=0{//获取相对位置
+            position--
+            e=e.Next()
+        }
+        l.MoveBefore(mark,e)//移动位置
+        
+    }
+    res:=[][]int{}
+    for e:=l.Front();e!=nil;e=e.Next(){
+        res=append(res,e.Value.([]int))
+    }
+    return res
+}
+```
+
 Javascript:
+
 ```Javascript
 var reconstructQueue = function(people) {
     let queue = []