From 825600a1d2c67f34fd9ecae91a171475c1ee1cb7 Mon Sep 17 00:00:00 2001
From: sugarlesss <jaded@foxmail.com>
Date: Mon, 25 Oct 2021 10:38:34 +0800
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---
 problems/面试题02.07.链表相交.md | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/problems/面试题02.07.链表相交.md b/problems/面试题02.07.链表相交.md
index f283b161..c5b8ed6f 100644
--- a/problems/面试题02.07.链表相交.md
+++ b/problems/面试题02.07.链表相交.md
@@ -38,7 +38,7 @@
 
 ![面试题02.07.链表相交_2](https://code-thinking.cdn.bcebos.com/pics/面试题02.07.链表相交_2.png)
 
-此时我们就可以比较curA和curB是否相同，如果不相同，同时向后移动curA和curB，如果遇到curA == curB，则找到焦点。
+此时我们就可以比较curA和curB是否相同，如果不相同，同时向后移动curA和curB，如果遇到curA == curB，则找到交点。
 
 否则循环退出返回空指针。