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添加 0102.二叉树的层序遍历.md 关于111.二叉树的最小深度的Python版本
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@ -1562,6 +1562,8 @@ JavaScript:
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# 111.二叉树的最小深度
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题目地址:https://leetcode-cn.com/problems/minimum-depth-of-binary-tree/
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相对于 104.二叉树的最大深度 ,本题还也可以使用层序遍历的方式来解决,思路是一样的。
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**需要注意的是,只有当左右孩子都为空的时候,才说明遍历的最低点了。如果其中一个孩子为空则不是最低点**
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@ -1597,7 +1599,35 @@ public:
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Java:
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Python:
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Python 3:
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```python 3
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# Definition for a binary tree node.
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# class TreeNode:
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# def __init__(self, val=0, left=None, right=None):
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# self.val = val
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# self.left = left
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# self.right = right
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class Solution:
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def minDepth(self, root: TreeNode) -> int:
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if root == None:
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return 0
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#根节点的深度为1
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queue_ = [(root,1)]
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while queue_:
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cur, depth = queue_.pop(0)
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if cur.left == None and cur.right == None:
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return depth
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#先左子节点,由于左子节点没有孩子,则就是这一层了
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if cur.left:
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queue_.append((cur.left,depth + 1))
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if cur.right:
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queue_.append((cur.right,depth + 1))
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return 0
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```
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Go:
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