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Update 0322.零钱兑换.md

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jianghongcheng
2023-06-04 23:32:42 -05:00
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problems/0322.零钱兑换.md
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@ -261,7 +261,7 @@ class Solution:
dp[0] = 0 dp[0] = 0
for coin in coins: for coin in coins:
for i in range(coin, amount + 1): for i in range(coin, amount + 1): # 进行优化，从能装得下的背包开始计算，则不需要进行比较
# 更新凑成金额 i 所需的最少硬币数量 # 更新凑成金额 i 所需的最少硬币数量
dp[i] = min(dp[i], dp[i - coin] + 1) dp[i] = min(dp[i], dp[i - coin] + 1)