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Update 222.完全二叉树的节点个数,添加C#递归版
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@ -867,6 +867,31 @@ impl Solution {
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}
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}
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}
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}
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```
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```
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### C#
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```C#
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// 递归
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public int CountNodes(TreeNode root)
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{
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if (root == null) return 0;
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var left = root.left;
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var right = root.right;
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int leftDepth = 0, rightDepth = 0;
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while (left != null)
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{
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left = left.left;
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leftDepth++;
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}
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while (right != null)
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{
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right = right.right;
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rightDepth++;
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}
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if (leftDepth == rightDepth)
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return (int)Math.Pow(2, leftDepth+1) - 1;
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return CountNodes(root.left) + CountNodes(root.right) + 1;
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}
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```
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<p align="center">
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<p align="center">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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<a href="https://programmercarl.com/other/kstar.html" target="_blank">
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